Question

我正在使用此功能删除Brackets并在其中：

+(NSString*)removeCharsBetweenBrackets:(NSString*)str {
NSRange range = [str rangeOfString:@"("];
if (range.location != NSNotFound) {
    NSRange range2 = [str rangeOfString:@")"];

    if (range2.location != NSNotFound) {
        NSString *str1 = [str substringToIndex:range.location];
        NSString *str2 = [str substringFromIndex:range2.location + 1];
        str = [NSString stringWithFormat:@"%@ %@",str1,str2];
    }
}

range = [str rangeOfString:@"["];
if (range.location != NSNotFound) {
    NSRange range2 = [str rangeOfString:@"]"];

    if (range2.location != NSNotFound) {
        NSString *str1 = [str substringToIndex:range.location];
        NSString *str2 = [str substringFromIndex:range2.location + 1];
        str = [NSString stringWithFormat:@"%@ %@",str1,str2];
    }
}

return str;
}

我打了两次去除两次，它完全删除了它。

问题是我有这样的字符串：

Mystring(blablabla)(*).mp3

* - Is a number. can be 0-999

我想只删除（*）。

我如何实现它？

编辑：

字符串可以是：

mystring(bla bla)(1).mp3
mystring(bla bla)(1123).mp3
mystring(99).mp3
mystring(9).mp3
mystring.mp3
mystring(bla bla).mp3

如果它存在，我需要删除(number)。

Answer 1

NSRegularExpression *regexp = [NSRegularExpression regularExpressionWithPattern:@"\\([0-9]{1,3}\\)" options:0 error:NULL];

NSString *result = [regexp stringByReplacingMatchesInString:string
                                                    options:0
                                                      range:NSMakeRange(0, [string length])
                                               withTemplate:@""];

Answer 2

NSString有一个非常有用的方法stringByReplacingOccurrencesOfString:withString:options:range:，如果您使用正则表达式搜索作为选项，它会完全符合您的要求：

NSString *string = ... // your string here;

NSString *pattern = @"\\(\\d+?\\)"; // Match one or more digits within a pair of brackets

NSString *cleaned = [string stringByReplacingOccurrencesOfString: pattern
                                                      withString: @"" 
                                                         options: NSRegularExpressionSearch 
                                                           range: NSMakeRange(0, string.length)];

您不必单独在变量中定义模式，但我发现它增强了可读性。

该模式与用于NSRegularExpression的模式相同，因此您可以在那里阅读。

Answer 3

使用以下正则表达式删除带数字的大括号

\([0-9]+\)

Answer 4

试试这个就像这样（*）

NSRegularExpression *regexp = [NSRegularExpression regularExpressionWithPattern:@"\\([0-9]*\\)" options:0 error:NULL];

NSString *result = [regexp stringByReplacingMatchesInString:string
                                                    options:0
                                                      range:NSMakeRange(0, [string length])
                                               withTemplate:@""];

Answer 5

+ (NSString *)removeCharsBetweenBrackets:(NSString *)str
{
    NSMutableString *strM = [str mutableCopy];
    NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:@"(\\(\\d+\\))"
                                                                           options:0
                                                                             error:NULL];

    NSArray *matches = [regex matchesInString:str options:0 range:NSMakeRange(0, [str length])];
    // Start from the back, since we're changing the size of the string.
    for (NSTextCheckingResult *result in [matches reverseObjectEnumerator])
    {
        [strM replaceCharactersInRange:[result range] withString:@"()"];
    }

    // Return an immutable version
    return [strM copy];
}

Answer 6

您可以使用正则表达式找到它：

NSString *string = @"abc(bud)(2).mp3";
NSError *error = NULL;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:@"\\([0-9]\\)" 
                                                                       options:NSRegularExpressionCaseInsensitive
                                                                         error:&error];
NSString *modifiedString = [regex stringByReplacingMatchesInString:string options:0 range:NSMakeRange(0, [string length]) withTemplate:@""];

NSLog(@"%@", modifiedString);

输出

ABC（芽）.MP3

NSString删除括号

6 个答案: