必须在zend2中返回一个字符串值。怎么样?

时间:2013-11-20 10:57:09

标签: doctrine-orm zend-framework2 zend-form zend-form-select

我遇到了zend2表单的问题。我创建了一个实体,它从数据库中获取一些数据并加入一些表......

这是实体:

class Campaigns
{
    /**
     * @ORM\Id
     * @ORM\GeneratedValue(strategy="AUTO")
     * @ORM\Column(type="integer")
     */
    protected $id;

    /**
     *
     * @ORM\Column(name="campaign_name", type="string")
     *
     */
    protected $campaigns;

    /**
     * @var mixed
     *
     * @ORM\ManyToMany(targetEntity="Application\Entity\Countries", cascade={"persist"}, orphanRemoval=false)
     * @ORM\JoinTable(name="campaigns_countries",
     *      joinColumns={@ORM\JoinColumn(name="campaign_id", referencedColumnName="id", onDelete="CASCADE")},
     *      inverseJoinColumns={@ORM\JoinColumn(name="country_id", referencedColumnName="id", onDelete="CASCADE")}
     *      )
     */
    protected $countries;

此代码下面是getter和setter,构造函数,add和remove函数。

他们是:

public function getId()
    {
        return $this->id;
    }

    public function setId($id)
    {
        $this->id = $id;
        return $this;
    }

    public function getCampaigns()
    {
        return $this->campaigns;
    }

    public function setCampaigns($campaigns)
    {
        $this->campaigns = $campaigns;
        return $this;
    }



    public function  addCampaigns($campaigns = null)
    {
        foreach ($campaigns as $c) {
            if (!$this->campaigns->contains($c)) {
                $this->campaigns->add($c);
            }
        }
    }

    public function removeCampaigns($campaigns)
    {
        foreach ($campaigns as $c) {
            if ($this->campaigns->contains($c)) {
                $this->campaigns->removeElement($c);
            }
        }
    }
    public function getCountries()
    {
        return $this->countries;
    }

    public function setCountries($countries)
    {
        $this->countries = $countries;
        return $this;
    }

    public function  addCountries($countries = null)
    {
        foreach ($countries as $c) {
            if (!$this->countries->contains($c)) {
                $this->countries->add($c);
            }
        }
    }

    public function removeCountries($countries)
    {
        foreach ($countries as $c) {
            if ($this->countries->contains($c)) {
                $this->countries->removeElement($c);
            }
        }
    } //construct for countries
    public function __construct()
    {
        $this->setCountries(new ArrayCollection());
    }

我的问题在于protected $countries。如果我在表单中添加属性值,它会为我提供在实体中找不到的“countries”属性。

如果我不添加它,而是使用__toString()函数,它会给我一个错误,说它无法将国家/地区转换为字符串...在__toString()函数中我添加了以下代码:

public function __toString()
{

return $this->countries;

}

感谢您的帮助!

AE

1 个答案:

答案 0 :(得分:1)

您说您想要一个包含所有相关国家/地区的字符串。以下代码演示了如何实现此目的:

$campaignCountryNames = array();

$campaignCountries = $campaign->getCountries(); 

foreach ($campaignCountries as $country) {
    // I assume your Country entity has a name property
    $campaignCountryNames[] = $country->getName();
}

echo implode(', ', $campaignCountryNames);