在sql中找到最大平均值

Question

我正在努力获得最高平均工资，我正在使用它：

select max (avg_salary)
from (select name, avg(salary) AS avg_salary
  from employee
  group by name);

但是在不使用子查询的情况下获得相同结果的另一种方法是什么？

Answer 1

SELECT AVG(salary)
FROM employee
GROUP BY name
ORDER BY AVG(salary) DESC
LIMIT 1

Answer 2

另一个选择是：

SELECT name, avg(salary) AS avg_salary
FROM employee
GROUP BY name
ORDER BY 2 DESC LIMIT 1;

Answer 3

改为使用

SELECT name, 
       avg(salary) AS avg_salary   
FROM employee 
GROUP BY name 
ORDER BY DESC avg_salary 
      LIMIT 1

Answer 4

试试这个...这种平均工资desc然后适用限制

SELECT AVG(salary),name
FROM employee GROUP BY name
ORDER BY AVG(salary) DESC
LIMIT 1

Answer 5

所有员工：

SELECT name, 
       AVG(salary) AS avg_salary 
FROM employee 
GROUP BY name 
ORDER BY avg_salary DESC

最多一名员工：

SELECT name, 
AVG(salary) AS avg_salary 
FROM employee 
GROUP BY name 
ORDER BY avg_salary DESC 
LIMIT 1