Question

我需要为我的班级制作一个程序，询问用户3年不同的年份并告诉他/她这个年份是否是闰年...这是我的代码（PS我们需要使用循环来做这样就保持循环）：

import java.util.Scanner;
import java.util.*;
public class BetterLeapYear
{

    public static void main(String[] args)
    {

        Scanner s = new Scanner(System.in);

        int year = s.nextInt();
        if (year > 1582){

        for (int i = 1; i <= 3; i++)
        {
            System.out.print ("Please enter a year: ");
            year = s.nextInt();
        }

        if (((year%4)== 0) && ((year%100)==0) && ((year%400)==0)) {
            System.out.print("That year was a leap year");
        }
        else if (((year%4)== 0) && ((year%100)==0) && ((year%400)!=0)){
            System.out.println("This year was not a leap year");
        }
        else if ((year%4)== 0){
            System.out.print("This year was a leap year");
        }
        else 
            System.out.print("This year was not a leap year");
        }
        else 
           System.out.print ("Please enter a year after 1582");
        }

    }

Answer 1

您首先应该让用户输入年份值。然后检查是否在1582年之前。并最后检查是否是闰年。

将代码year = s.nextInt();和if (year < 1582) {放入for循环以接收输入的年份，并检查输入的年份是否在1582之后。

这三个步骤如下：

像

for (int i = 1; i <= 3; i++) {
        /*
         * Step#1 Receive a year value 
         */
        System.out.println("Please enter a year: ");
        year = s.nextInt();

        /*
         * Step#2 Check if the year is after 1580 or not.
         * 
         */
        if (year < 1582) {
            System.out.println("Please enter a year after 1582");
        } else {
            /*
             * Step#3 Check whether the year entered is leap year or not 
             */
            if (((year % 4) == 0) && ((year % 100) == 0)
                    && ((year % 400) == 0)) {
                System.out.println("That year was a leap year");
            } else if (((year % 4) == 0) && ((year % 100) == 0)
                    && ((year % 400) != 0)) {
                System.out.println("This year was not a leap year");
            } else if ((year % 4) == 0) {
                System.out.println("This year was a leap year");
            } else
                System.out.println("This year was not a leap year");
        }
    }

程序不会运行....日食中的Java

1 个答案: