Question

我正在尝试使用C语言创建一个程序，该程序可以接收数组结构（非并行）形式的员工信息，并将其输出到文本文件中。该计划将比较工作代码并计算员工的佣金率。我有两个问题：

1 - 即使我输入TEL，SAL，SSR之一，salesPerson的佣金也总是为0。这是我的字符串比较的问题吗？

2 - 如何将结果输出到文本文件中（在项目文件夹中）？

编辑 - 我已经想出如何将文件打印到txt中。谢谢大家的帮助！

#include "stdafx.h"
#include <string.h>
#include <stdlib.h>

//job codes
char TEL[4] = "TEL";
char SAL[4] = "SAL";
char SSR[4] = "SSR";

//create a sales person structure
struct salesPerson
{
    char name[31];
    int salesID;
    char jobCode[4];
    double totalSales;
    double commission;
}e[10]; //make an array of 10 employees

int _tmain(int argc, _TCHAR* argv[])
{
    //get employee info
    for(int i=0; i<3; i++)
    {
        printf("\nEnter the sales person's name: ");
        scanf(" %s", &e[i].name);
        printf("\nEnter the sales person's ID: \n");
        scanf(" %d%*c", &e[i].salesID);
        printf("\nEnter the sales person's job code: \n");
        scanf(" %s", &e[i].jobCode);
        printf("\nEnter the total sales of the sales person: ");
        scanf(" %lf", &e[i].totalSales);

        //determine commission based on jobCode
        if(strcmp(e[i].jobCode, TEL) == 0)
        {
            e[i].commission = e[i].totalSales*0.02;
        }
        if(strcmp(e[i].jobCode, SAL) == 0)
        {
            e[i].commission = e[i].totalSales*0.05;
        }
        if(strcmp(e[i].jobCode, SSR) == 0)
        {
            e[i].commission = e[i].totalSales*0.07;
        }
        else
        {
            printf("\n----------");
        }
    }

    printf("\n%d\n", e[0].commission);
    printf("\n%d\n", e[1].commission);
    printf("\n%d\n", e[2].commission);

    //print stuff to txt file
    FILE *fpOut, *fpIn;
    /*
    if ((fpIn = fopen("c:\\temp\\salesEmployees.txt", "w")) == NULL)
    {
        printf("Error opening the file for processing\n\n");
    }
    else
    {
        fpOut = fopen("c:\\temp\\salesEmployees.txt", "w");
        for(int i=0; i<3; i++)
        {
            //fscanf(fpIn,"%[^\n]", &e[i].name);
            //fscanf(fpIn,"%f%*c", &e[i].salesID);

            fprintf(fpOut, "\nName: %s", e[i].name);
            fprintf(fpOut, "\nSalesID: %d*c ", e[i].salesID);
            fprintf(fpOut, "\nJob code: %s ", e[i].jobCode);
            fprintf(fpOut, "\nTotal sales: %.2lf", e[i].totalSales);
            fprintf(fpOut, "\nCommission earned: %.2lf", e[i].commission);
            fprintf(fpOut, "\n\n");
        }

        //fclose(fpOut);
    }*/

}

Answer 1

回答问题的第二部分（关于程序崩溃，并将文件保存在同一目录中）：打开相同的文件进行输入和输出，而不是在它们之间关闭;不确定为什么输入就在那里。假设（为简单起见）您只想保存到从键盘输入的文件，您可以删除对fpIn的所有引用。至于“将文件保存在同一文件夹中” - 只需使用相对路径。当您从c:\my\dir开始运行时，打开文件salesOutput.txt会将其写入c:\my\dir\salesOutput.txt。

完整且有效的代码（一些更改以适应我的编译器设置......）：

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

//job codes
char TEL[4] = "TEL";
char SAL[4] = "SAL";
char SSR[4] = "SSR";

//create a sales person structure
struct salesPerson
{
    char name[31];
    int salesID;
    char jobCode[4];
    double totalSales;
    double commission;
}e[10]; //make an array of 10 employees

int main(int argc, char* argv[])
{
    //get employee info
    int i;
    for(i=0; i<3; i++)
    {
        printf("\nEnter the sales person's name: ");
        scanf(" %s", &e[i].name);
        printf("\nEnter the sales person's ID: \n");
        scanf(" %d%*c", &e[i].salesID);
        printf("\nEnter the sales person's job code: \n");
        scanf(" %s", &e[i].jobCode);
        printf("\nEnter the total sales of the sales person: ");
        scanf(" %lf", &e[i].totalSales);

        //determine commission based on jobCode
        if(strcmp(e[i].jobCode, TEL) == 0)
        {
            e[i].commission = e[i].totalSales*0.02;
        }
        if(strcmp(e[i].jobCode, SAL) == 0)
        {
            e[i].commission = e[i].totalSales*0.05;
        }
        if(strcmp(e[i].jobCode, SSR) == 0)
        {
            e[i].commission = e[i].totalSales*0.07;
        }
        else
        {
            printf("\n----------");
        }
    }

    printf("\n%lf\n", e[0].commission);
    printf("\n%lf\n", e[1].commission);
    printf("\n%lf\n", e[2].commission);

    //print stuff to txt file
    FILE *fpOut;
    {
        if((fpOut = fopen("salesEmployees.txt", "w")) == NULL)
        {
          printf("Unable to open file - quitting\n");
          return -1;
        };
        int i;
        for(i=0; i<3; i++)
        {
            fprintf(fpOut, "\nName: %s", e[i].name);
            fprintf(fpOut, "\nSalesID: %d*c ", e[i].salesID);
            fprintf(fpOut, "\nJob code: %s ", e[i].jobCode);
            fprintf(fpOut, "\nTotal sales: %.2lf", e[i].totalSales);
            fprintf(fpOut, "\nCommission earned: %.2lf", e[i].commission);
            fprintf(fpOut, "\n\n");
        }
        fclose(fpOut);
    }
}

显然，添加I / O，输入错误检查等是可取的（也是必要的） - 但是这应该让你超越“它不工作，我不知道为什么”这一点。我确实想知道为什么你在销售ID的打印输出中有*c - 它只是被添加到输出中 - 但我决定不删除它。

祝你好运！

Answer 2

始终查看编译器的警告。

printf("\n%d\n", e[0].commission);

您给出整数格式说明符，但参数为double。它的前几个字节可能为零 - 这就是结果打印为零的原因。尝试将其更改为：

printf("\n%.2lf\n", e[0].commission);

你将获得美元和美分的佣金。其他行也一样。

C语言 - 将数组打印到文本文件中

2 个答案: