function SearchMembers()
{
// grab user input
//$my_gender = $this->security->xss_clean($this->input->post('my_gender'));
$this->security->xss_clean($this->input->post('looking_for_gender'));
$age_from = $this->security->xss_clean($this->input->post('age_from'));
$age_to = $this->security->xss_clean($this->input->post('age_to'));
$member_postcode = $this->security->xss_clean($this->input->post('postcode'));
$member_distance = $this->security->xss_clean($this->input->post('distance'));
// Prep the query
$this->db->where('Gender', $looking_for_gender);
$this->db->where('Age >=', $age_from);
$this->db->where('Age <=', $age_to);
$miles = $this->search_form_model->distCalc('postcode',$member_postcode);
$this->db->where($miles < $member_distance);
// Run the query
$query = $this->db->get('member');
// Let's check if there are any results
if ($query->num_rows() > 0)
{
foreach ($query->result() as $row)
{
return $query->result();
}
// If the previous process did not validate
// then return false.
return false;
}
}
希望有人可以提供帮助。我正在以英里为单位执行两个邮政编码之间的距离检查,并添加距离结果不到距离的所有邮政编码。
以前我所做的就是遍历所有匹配性别和年龄的邮政编码,然后比距离检查少了几英里但结果是json数组,现在想要在mysql查询中执行它,如果可能的话,理想情况下使用codeigniter框架。非常感谢
答案 0 :(得分:0)
首先,使用绑定参数而不是XSS clean:
请参阅Does CodeIgniter automatically prevent SQL injection?
假设你有经度和纬度,你可以添加它来选择距离
$this->db->select("
Gender,Age, --etc.
(
(
ACOS(
SIN($lat * PI() / 180)
* SIN(`lat` * PI() / 180)
+ COS($lat * PI() / 180)
* COS(`lat` * PI() / 180)
* COS(($lon - `lon`)
* PI() / 180))
* 180 / PI()
) * 60 * 1.1515
) AS distance
");
您还需要order by
进行排序,having
只能返回距离内的值。
$this->db->order_by('distance');
$this->db->having('distance <= '.$member_distance.' OR postcode='.$member_postcode);