Python .strip()不会在if语句之外保存?

时间:2013-11-19 18:26:06

标签: python scrapy stocks

我从网页上提取数据。我遇到的一个问题是它提取了很多空白,我选择使用其他人建议的.strip()。我遇到了一个问题

if a.strip():
    print a
if b.strip():
    print b

返回:

a1
b1
.
.
.

但是这个:

if a.strip():
    aList.append(a)
if b.strip():
    bList.append(b)
print aList, bList

返回:

a1



    b1

我试图用这里的.strip()来模拟我删除的空格,但是你明白了。无论出于何种原因,它都会将空白添加到列表中,即使我告诉它不要。我甚至可以在if语句中打印列表,它也可以正确显示,但无论出于何种原因,当我决定在if语句之外打印时它不能按照我的意图工作。

这是我的整个代码:

# coding: utf-8
from scrapy.spider import BaseSpider
from scrapy.selector import HtmlXPathSelector
from scrapy.contrib.exporter import CsvItemExporter
import re
import csv
import urlparse
from stockscrape.items import EPSItem
from itertools import izip

class epsScrape(BaseSpider):
        name = "eps"
        allowed_domains = ["investors.com"]
        ifile = open('test.txt', "r")
        reader = csv.reader(ifile)
        start_urls = []
        for row in ifile:
                url = row.replace("\n","")
                if url == "symbol":
                        continue
                else:
                        start_urls.append("http://research.investors.com/quotes/nyse-" + url + ".htm")
        ifile.close()

        def parse(self, response):
                f = open("eps.txt", "a+")
                sel = HtmlXPathSelector(response)
                sites = sel.select("//div")
#               items = []
                for site in sites:
                        symbolList = []
                        epsList = []
                        item = EPSItem()
                        item['symbol'] = site.select("h2/span[contains(@id, 'qteSymb')]/text()").extract()
                        item['eps']  = site.select("table/tbody/tr/td[contains(@class, 'rating')]/span/text()").extract()
                        strSymb = str(item['symbol'])
                        newSymb = strSymb.replace("[]","").replace("[u'","").replace("']","")
                        strEps = str(item['eps'])
                        newEps = strEps.replace("[]","").replace(" ","").replace("[u'\\r\\n","").replace("']","")
                        if newSymb.strip():
                                symbolList.append(newSymb)
#                               print symbolList
                        if newEps.strip():
                                epsList.append(newEps)
#                               print epsList
                        print symbolList, epsList
                for symb, eps in izip(symbolList, epsList):
                        f.write("%s\t%s\n", (symb, eps))
                f.close()

2 个答案:

答案 0 :(得分:8)

strip不会就地修改字符串。它返回一个带有空白的新字符串。

>>> a = '    foo      '
>>> b = a.strip()
>>> a
'    foo      '
>>> b
'foo'

答案 1 :(得分:0)

我弄清楚是什么造成了混乱。它是我声明变量/列表的位置。我在for循环中声明它所以每次迭代它重写时,空白列表或变量与if语句的结果相同。