Twitter请求令牌总是在python中失败，401

Question

我正在使用urllib和urllib2从推特获取请求令牌https://dev.twitter.com/docs/auth/implementing-sign-twitter，代码如下。任何人都可以看到，我做错了什么？我得到＆＃39; urllib2.HTTPError：HTTP错误401：未经授权＆＃39;

#! env python

import sys                                                          
import os                                                           
import urllib                                                        
import urllib2                                                      
import uuid                                                         
import time                                                         
import base64
import string                                                       

# 1. Obtain a request token                                         
# 2. Redirect the user                                              
# 3. Convert the request token to an access token                   

consumer_key=           "xxxxxxx"                     
consumer_secret=        "xxxxxxxxxxxxxxx"

# Request token URL:    https://api.twitter.com/oauth/request_token 
# Authorize URL:        https://api.twitter.com/oauth/authorize     
# Access token URL:     https://api.twitter.com/oauth/access_token  

nonce = base64.b32encode(str(uuid.uuid4().hex))                     
# example: MYZTMMRYMEYDQN3FMFSDIYJXGNRDCMBWG42TAMJUGVTGGMZRMFSA====
nonce = nonce.rstrip('=') 
print 'Nonce', nonce                                                

data = { 'oauth_callback'           : 'http://www.gooogle.com',     
         'oauth_consumer_key'       : 'bwKT66akiJSin30L1mGnQ',      
         'oauth_nonce'              : nonce,                        
         'oauth_timestamp'          : int(time.time()),             
         'oauth_version'            : "1.1"                         
}                                                                   

url_values = urllib.urlencode(data)                                 
url = 'https://api.twitter.com/oauth/request_token'
full= url + '?' + url_values                       
data = urllib2.urlopen(full)                       

这里必须包含所有查询参数吗？