我在尝试使用Indy将xml发布到Web服务时遇到了一些麻烦。
我的客户端是使用Indy 10.0.52的delphi中的一个类,我的api服务器是django-tastypie。 我在服务器上的堆栈是:
Django==1.5.1
defusedxml==0.4.1
django-tastypie==0.10.0
lxml==3.2.3
mimeparse==0.1.3
其他客户端(如普通卷曲,python,js)发布到相同的资源没有问题。 例如:
$ curl --dump-header - -H "Content-Type: application/xml" -H "Authentication: Basic 875488" -k -X POST --data '<object>...</object>' https://www....object/?format=xml
HTTP/1.1 201 CREATED
Date: Tue, 19 Nov 2013 10:28:01 GMT
Server: Apache/2.2.14 (Ubuntu)
Access-Control-Allow-Headers: Origin,Authorization,Content-Type,Accept
Vary: Accept,Accept-Encoding
Location: https://www....object/12
Access-Control-Allow-Credentials: true
Access-Control-Allow-Origin: *
Access-Control-Allow-Methods: POST,GET,OPTIONS,PUT,DELETE
Content-Length: 0
Content-Type: text/html; charset=utf-8
但是使用Indy我总是得到:'501未实施'。 这是我的程序:
procedure TRestObject.post( postURL:String; doc:IXMLDocument );
var
aStream : TMemoryStream;
data : TStringStream;
xmlString, urlString : String;
begin
aStream := TMemoryStream.Create;
data := TStringStream.Create('');
try
http.HandleRedirects := True;
http.ReadTimeout := 50000;
// encoding
xmlString := doc.XML.Strings[1];
urlString := URLencode(xmlString);
showmessage(xmlString);
//showmessage(urlString);
data.WriteString( urlString );
aStream.Write( urlString[1], Length(urlString) * SizeOf(Char) );
with http do
begin
try
Response.KeepAlive := False;
//Post( postURL, data, aStream );
Post( postURL, aStream );
except
on E: EIdException do
showmessage('Exception (class '+ E.ClassName +'): ' + E.Message);
on E: EIdHTTPProtocolException do
showmessage('Protocol Exception (HTTP status '+ IntToStr(E.ErrorCode) +'): ' + E.Message);
on E: EIdSocketError do
showmessage('Socket Error ('+ IntToStr(E.LastError) +'): ' + E.Message);
end;
end;
finally
aStream.Free;
data.Free;
end;
end;
'http'是Indy TIdHTTP的成员实例。
有人可以指出我做错了吗?
答案 0 :(得分:1)
在发布之前,您没有将流的Position
重置为0,您甚至根本没有发布XML流(您已将其注释掉)。您也没有考虑字符编码,也没有复制传递给curl的相同属性。
试试这个:
procedure TRestObject.post( postURL:String; doc:IXMLDocument );
var
aStream: TMemoryStream;
data : TStringStream;
xmlString : String;
begin
aStream := TMemoryStream.Create;
try
http.HandleRedirects := True;
http.ReadTimeout := 50000;
// encoding
xmlString := doc.XML.Text;
ShowMessage(xmlString);
data := TStringStream.Create(xmlString, TEncoding.UTF8);
try
http.Request.ContentType := 'application/xml';
http.Request.Connection := 'close';
try
http.Post( postURL, data, aStream );
except
on E: EIdHTTPProtocolException do
ShowMessage('Protocol Exception (HTTP status '+ IntToStr(E.ErrorCode) +'): ' + E.Message);
on E: EIdSocketError do
ShowMessage('Socket Error ('+ IntToStr(E.LastError) +'): ' + E.Message);
on E: Exception do
ShowMessage('Exception (class '+ E.ClassName +'): ' + E.Message);
end;
finally
data.Free;
end;
finally
aStream.Free;
end;
end;