如何以有效的方式在J2ME中拆分字符串?
标准版(J2SE)中有StringTokenizer
或String.split(String regex)
,但微版本(J2ME,MIDP)中没有它们。
答案 0 :(得分:11)
J2ME的StringTokenizer类有一些实现。这个Ostermiller很可能包含您需要的功能
另请参阅this page on Mobile Programming Pit Stop进行一些修改以及以下示例:
String firstToken;
StringTokenizer tok;
tok = new StringTokenizer("some|random|data","|");
firstToken= tok.nextToken();
答案 1 :(得分:3)
没有内置的方法来分割字符串。你必须自己编写它
String.indexOf()
和String.substring()
。不难。
答案 2 :(得分:3)
String.split(...)在J2SE中可用,但不在J2ME中 您需要编写自己的算法:related post with sample solution。
答案 3 :(得分:3)
我希望这个会帮助你...这是我在我的应用程序中使用的我自己的实现。当然,这仍然可以优化。我没有时间去做...而且,我在这里工作的是StringBuffer。只需重构一下就可以使用String了。
public static String[] split(StringBuffer sb, String splitter){
String[] strs = new String[sb.length()];
int splitterLength = splitter.length();
int initialIndex = 0;
int indexOfSplitter = indexOf(sb, splitter, initialIndex);
int count = 0;
if(-1==indexOfSplitter) return new String[]{sb.toString()};
while(-1!=indexOfSplitter){
char[] chars = new char[indexOfSplitter-initialIndex];
sb.getChars(initialIndex, indexOfSplitter, chars, 0);
initialIndex = indexOfSplitter+splitterLength;
indexOfSplitter = indexOf(sb, splitter, indexOfSplitter+1);
strs[count] = new String(chars);
count++;
}
// get the remaining chars.
if(initialIndex+splitterLength<=sb.length()){
char[] chars = new char[sb.length()-initialIndex];
sb.getChars(initialIndex, sb.length(), chars, 0);
strs[count] = new String(chars);
count++;
}
String[] result = new String[count];
for(int i = 0; i<count; i++){
result[i] = strs[i];
}
return result;
}
public static int indexOf(StringBuffer sb, String str, int start){
int index = -1;
if((start>=sb.length() || start<-1) || str.length()<=0) return index;
char[] tofind = str.toCharArray();
outer: for(;start<sb.length(); start++){
char c = sb.charAt(start);
if(c==tofind[0]){
if(1==tofind.length) return start;
inner: for(int i = 1; i<tofind.length;i++){ // start on the 2nd character
char find = tofind[i];
int currentSourceIndex = start+i;
if(currentSourceIndex<sb.length()){
char source = sb.charAt(start+i);
if(find==source){
if(i==tofind.length-1){
return start;
}
continue inner;
} else {
start++;
continue outer;
}
} else {
return -1;
}
}
}
}
return index;
}
答案 4 :(得分:2)
这取决于你想要实现的目标,但函数String.substring()将在某处:
String myString = "Hello World";
这将打印从索引6开始到字符串结尾的子字符串:
System.out.println(myString.substring(6));
这将打印从索引0开始直到索引5的子字符串:
System.out.println(myString.substring(0,5));
输出上述所有代码:
World Hello
将此与其他字符串函数(indexOf()
等)相结合,以达到预期的效果!
重新阅读您的问题,看起来您可能一直在寻找String.split()
。这将根据给定的正则表达式将输入字符串拆分为字符串数组:
String myString = "Hi-There-Gang";
String[] splitStrings = myString.split("-");
这将导致splitStrings数组包含三个字符串"Hi"
,"There"
和"Gang"
。
再次重新阅读您的问题,String.split
在J2ME中不可用,但使用substring
和indexOf
可以达到同样的效果。
答案 5 :(得分:1)
public static Vector splitDelimiter(String text, char delimiter) {
Vector splittedString = null;
String text1 = "";
if (text != null) {
splittedString = new Vector();
for (int i = 0; i < text.length(); i++) {
if (text.charAt(i) == delimiter) {
splittedString.addElement(text1);
text1 = "";
} else {
text1 += text.charAt(i);
// if(i==text.length()-1){
// splittedString.addElement(text1);
// }
}
}
splittedString.addElement(text1);
}
return s
}
您可以使用此方法拆分分隔符。
答案 6 :(得分:1)
在J2ME中没有拆分,但是您可以使用此代码进行拆分。此代码仅适用于1个simbol分隔符! 使用NetBeans.File \ Create Project \ Java ME \ MobileApplication \设置项目名称(拆分)\设置checkmark.Delete(Midlet.java)中的所有代码。复制此代码并过去(Midlet.java)。
//IDE NetBeans 7.3.1
//author: UserSuperPupsik
//email: usersuperpupsik@gmail.com
package split;
import javax.microedition.lcdui.*;
import javax.microedition.midlet.*;
import java.util.Vector;
public class Midlet extends MIDlet {
public String e1;
public Vector v=new Vector();
public int ma;
int IsD=0;
int vax=0;
public String out[];
private Form f;
public void split0(String text,String delimiter){
if (text!=""){
IsD=0;
int raz=0;
//v.removeAllElements();
v.setSize(0);
int io;
String temp="";
int ni=(text.length()-1);
for(io=0;io<=ni;io++){
char ch=text.charAt(io);
String st=""+ch;
if(io==0 && st.equals(delimiter)){IsD=1;}
if(!st.equals(delimiter)){temp=temp+st;} //Not equals (!=)
else if(st.equals(delimiter)&&temp!="")//equals (==)
{
IsD=1;
//f.append(temp);
v.addElement(temp);
temp="";
}
if(io==ni && temp!="") {
v.addElement(temp);
temp="";
}
if((io==ni)&&IsD==0&&temp!=""){v.addElement(temp);}
}
if(v.size()!=0){
ma=(v.size());
out=new String[ma];
v.copyInto(out);
}
//else if(v.size()==0){IsD=1; }
}
}
public void method1(){
f.append("\n");
f.append("IsD: " +IsD+"");
if (v.size()!=0){
for( vax=0;vax<=ma-1;vax++){
f.append("\n");
f.append(out[vax]);
}
}
}
public void startApp() {
f=new Form("Hello J2ME!");
Display.getDisplay(this).setCurrent(f);
f.append("");
split0("Hello.World.Good...Luck.end" , ".");
method1();
split0(".",".");
method1();
split0(" First WORD2 Word3 "," ");
method1();
split0("...",".");
method1();
}
public void pauseApp() {
}
public void destroyApp(boolean unconditional) {
}
}
位于数组中的Splited元素称为(out)。例如out [1]:Hello。 祝你好运!!!
答案 7 :(得分:0)
另一种替代解决方案:
public static Vector split(String stringToSplit, String separator){
if(stringToSplit.length<1){
return null;
}
Vector stringsFound = new Vector();
String remainingString = stringToSplit;
while(remainingString.length()>0){
int separatorStartingIndex = remainingString.indexOf(separator);
if(separatorStartingIndex==-1){
// Not separators found in the remaining String. Get substring and finish
stringsFound.addElement(remainingString);
break;
}
else{
// The separator is at the beginning of the String,
// Push the beginning at the end of separator and continue
if(remainingString.startsWith(separator)){
remainingString = remainingString.substring(separator.length());
}
// The separator is present and is not the beginning, add substring and continue
else{
stringsFound.addElement(remainingString.substring(0, separatorStartingIndex));
remainingString = remainingString.substring(separatorStartingIndex + separator.length());
}
}
}
return stringsFound;
}