Question

我以这种方式呼叫webservice ..

public static String POST(String url, ArrayList<ModelLatLog> list,Context con){
 InputStream inputStream = null;
 String result = "";
 AppLog.logString(TAG+"URL     : "+url);
 AppLog.logString(TAG+"ListSize: "+list.size());

 try {
    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httpPost = new HttpPost(url);
    String json = "[";
    for(int j=0;j<list.size();j++){            
        JSONObject jsonObject = new JSONObject();
        jsonObject.accumulate("DId", ""+list.get(j).get_idDevice());
        jsonObject.accumulate("Lat", ""+list.get(j).getLat());
        jsonObject.accumulate("Long", ""+list.get(j).getLong());
        jsonObject.accumulate("DIn", ""+list.get(j).getDt());
        jsonObject.accumulate("TIn", ""+list.get(j).getTm());
        jsonObject.accumulate("Dce", ""+list.get(j).getDce());
        if(j==0 ){
            json = json+""+jsonObject.toString();
            AppLog.logString(TAG+"if j: "+j);
        }
        else{
            json = json+","+jsonObject.toString();
            AppLog.logString(TAG+"else j: "+j);
        }
    }
    json = json+"]";
    AppLog.logString(TAG+"JSON: "+json);
    StringEntity se = new StringEntity(json);
    httpPost.setEntity(se);
    httpPost.setHeader("Accept", "application/json");
    httpPost.setHeader("Content-type", "application/json");
    HttpResponse httpResponse = httpclient.execute(httpPost);
    int resopnceStatus = httpResponse.getStatusLine().getStatusCode();
    AppLog.logString(TAG+"set data resopnceStatus: "+resopnceStatus);
    inputStream = httpResponse.getEntity().getContent();
    if(inputStream != null)
        result = convertInputStreamToString(inputStream);
    else
        result = "Did not work!";

} catch (Exception e) {
    e.printStackTrace();
    AppLog.logString("InputStream"+ e.getLocalizedMessage());
}
return result;
}

AppLog不是它的log.d

它给了我像

这样的错误

11-19 18:15:39.088: I/Service(32261): Utility: set data resopnceStatus: 500
11-19 18:15:39.096: I/Service(32261): result: <?xml version="1.0" encoding="utf-8"?><soap:Envelope xmlns:soap="http://www.w3.org/2003/05/soap-envelope" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"><soap:Body><soap:Fault><soap:Code><soap:Value>soap:Receiver</soap:Value></soap:Code><soap:Reason><soap:Text xml:lang="en">Server was unable to process request. ---&gt; Data at the root level is invalid. Line 1, position 1.</soap:Text></soap:Reason><soap:Detail /></soap:Fault></soap:Body></soap:Envelope>

Answer 1

看起来web服务正在向您返回错误，因此HTTP POST调用实际上有效。

你发送的格式是否正确？看起来像是期待XML请求而你发送JSON。

Answer 2

为什么你这么负担...... 只需使用排球服务......它会照顾好每一件事......

在Volley中使用 StringRequest 。你的任务很容易...... 在此处下载volley示例

Answer 3

如果你还没有弄清楚你的问题，我相信ksoap2对于处理android上的webservices更直观，这个链接有一个很好的例子。

is there clear Example of Android ksoap2 returning array of objects from .Net Web service?

Android调用webservice问题

3 个答案: