Question

我们有一个网站。在某些情况下，用户可以使用内置浏览器从Facebook App或VKontakte App打开。我想在Safari或其他浏览器中打开一个链接。但不是在这个WebView中。

任何可以告诉WebView的HTML属性或其他东西本身都不能打开此链接吗？

更新：我不是App开发人员。我是网站开发人员。我没有任何访问Facebook App的权限。我需要强制Facebook App打开不在其内置浏览器中的链接。

Answer 1

您可以使用UIWebViewDelegate：

-(BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType {
    if(UIWebViewNavigationTypeLinkClicked == navigationType /*you can add some checking whether link should be opened in Safari */) {

        [[UIApplication sharedApplication] openURL:[request URL]];
        return NO;
    }
    return YES;
}

Answer 2

Web视图包含一些委托方法，用于从该委托方法中查找单击事件，您需要像这样调用URL

 [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"www.google.com"]];

这是在单击Web视图中的任何链接时将触发的委托方法

    -(BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType
{
if (navigationType == UIWebViewNavigationTypeLinkClicked) {
{
   [[UIApplication sharedApplication] openURL:[request URL]];
}

}

只需将网址与URLRequest区分开来。

Answer 3

如果您设置了UIWebViewDelegate，则可以使用方法

- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType;

使用此方法，我们可以阻止或允许在UIWebView或移动浏览器中打开某些链接/网址。

所以我们可以做类似

的事情

- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType
{
    // We only want to block links
    if(navigationType == UIWebViewNavigationTypeLinkClicked) {
        NSString *url = [[request URL] absoluteString];
        if([url isEqualToString:@"http://www.google.co.uk"]) {
            // If the requested url is a link and is http://www.google.co.uk block it from loading in the UIWebView and load it in the mobile browser.
            if([[UIApplication sharedApplication] canOpenUrl:[request URL]]) {
                // We should be checking to make sure we can open it first, for whatever reason we might not be able to and we don't want to give the user a bad journey.
                [[UIApplication sharedApplication] openURL:[request URL]];

                // We also need to tell our UIWebView not to do anything so we need to return NO.
                return NO;
            }
        }
    }

    // If all is OK and we are happy for any other link to be included then just return YES and continue.
    return YES;
}

如果您想阻止所有链接，只需删除isEqualToString: if statement，或者只需将else if添加到if statement即可阻止某些链接。此代码执行以下两项操作之一：它会在UIWebView中加载点击的链接网站，或者如果网站通过if statements，则会在移动浏览器中加载网站。

<强>更新

事实证明，用户没有objective-c他们正在执行html的事情，这不是原始问题，但是因为这可以帮助用户将来我会把答案留在这里。

修改

由于用户正在使用html尝试将用户引导至移动浏览器，因此他们所寻找的内容称为URL方案。不幸的是，我不相信会有iOS 7的任何URL方案会打开safari移动浏览器。之前已经问过这个问题，所以我不会再坐在这里再说一遍我只会引导你回答问题Open Mobile Safari from a Link in a WebView

Answer 4

//codigo para abrir no safari
-(BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType; {

NSURL *requestURL =[ [ request URL ] retain ];
if ( ( [ [ requestURL scheme ] isEqualToString: @”http” ] || [ [ requestURL scheme ] isEqualToString: @”https” ] || [ [ requestURL scheme ] isEqualToString: @”mailto” ])&& ( navigationType == UIWebViewNavigationTypeLinkClicked ) )
{ return ![ [ UIApplication sharedApplication ] openURL: [ requestURL autorelease ] ]; } [     requestURL release ]; return YES;

}

如何强制UIWebView在浏览器中打开链接？

4 个答案: