Question

因为这似乎是我必须做的才能产生这种效果：

$arr = ['a'=>'first', 'b'=>'second', ...];
$iter = new ArrayIterator( $arr );

// Do a bunch of iterations...
$iter->next();
// ...

$new_iter = new ArrayIterator( $arr );
while( $new_iter->key() != $iter->key() ) {
    $new_iter->next();
}

编辑：另外，为了清楚起见，我是否应该使用unset()修改基本数组？我认为数组迭代器存储它自己的基本数组副本，因此使用offsetUnset()似乎不对。

Answer 1

ArrayIterator未实现tell()功能，但您可以模拟此功能，然后使用seek()转到所需位置。这是一个扩展类，它就是这样做的：

<?php
    class ArrayIteratorTellable extends ArrayIterator {
        private $position = 0;

        public function next() {
            $this->position++;
            parent::next();
        }

        public function rewind() {
            $this->position = 0;
            parent::rewind();
        }

        public function seek($position) {
            $this->position = $position;
            parent::seek($position);
        }

        public function tell() {
            return $this->position;
        }

        public function copy() {
            $clone = clone $this;
            $clone->seek($this->tell());
            return $clone;
        }
    }
?>

使用：

<?php
    $arr = array('a' => 'first', 'b' => 'second', 'c' => 'third', 'd' => 'fourth');
    $iter = new ArrayIteratorTellable( $arr );

    $iter->next();

    $new_iter = new ArrayIteratorTellable( $arr );

    var_dump($iter->current()); //string(6) "second"
    var_dump($new_iter->current()); //string(6) "first"

    $new_iter->seek($iter->tell()); //Set the pointer to the same as $iter

    var_dump($new_iter->current()); //string(6) "second"
?>

DEMO

或者，您可以使用自定义copy()函数来克隆对象：

<?php
    $arr = array('a' => 'first', 'b' => 'second', 'c' => 'third', 'd' => 'fourth');
    $iter = new ArrayIteratorTellable( $arr );

    $iter->next();

    $new_iter = $iter->copy();

    var_dump($iter->current()); //string(6) "second"
    var_dump($new_iter->current()); //string(6) "second"
?>

DEMO

Answer 2

我想到的唯一解决方案是使用当前数组的副本

$arr = ['a'=>'first', 'b'=>'second'];
$iter = new ArrayIterator( $arr );
// Do a bunch of iterations...
$iter->next();
var_dump($iter->current());
// ...
$arr2 = $iter->getArrayCopy();
$new_iter = new ArrayIterator( $arr2 );

while( $new_iter->key() != $iter->key() ) {
    var_dump($new_iter->current());
    $new_iter->next();    
}

如何复制ArrayIterator以保留其当前的迭代位置？

2 个答案:

使用：