使用Javamail访问Microsoft Exchange邮箱(IMAP,MS Exchange)

时间:2013-11-19 08:41:32

标签: java authentication exchange-server javamail imap

我需要通过IMAPS JavaMail连接到Microsoft Exchange Server。首先,我得到了:

A1 NO AUTHENTICATE failed.
javax.mail.AuthenticationFailedException: AUTHENTICATE failed.
我的调试器中的

异常。

然后,我禁用了一些身份验证协议:

imapProps.setProperty("mail.imaps.auth.plain.disable", "true");
imapProps.setProperty("mail.imaps.auth.ntlm.disable", "true");
imapProps.setProperty("mail.imaps.auth.gssapi.disable", "true");

这是我得到的新例外(我附上了整个日志):

DEBUG: setDebug: JavaMail version 1.4.4
DEBUG: getProvider() returning javax.mail.Provider[STORE,imaps,com.sun.mail.imap.IMAPSSLStore,Sun Microsystems, Inc]
DEBUG: mail.imap.fetchsize: 16384
DEBUG: mail.imap.statuscachetimeout: 1000
DEBUG: mail.imap.appendbuffersize: -1
DEBUG: mail.imap.minidletime: 10
DEBUG: disable AUTH=PLAIN
DEBUG: disable AUTH=NTLM
DEBUG: enable STARTTLS
DEBUG: trying to connect to host "host.domain.com", port 993, isSSL true
* OK The Microsoft Exchange IMAP4 service is ready.
A0 CAPABILITY
* CAPABILITY IMAP4 IMAP4rev1 AUTH=NTLM AUTH=GSSAPI AUTH=PLAIN UIDPLUS CHILDREN IDLE  NAMESPACE LITERAL+
A0 OK CAPABILITY completed.
DEBUG IMAP: AUTH: NTLM
DEBUG IMAP: AUTH: GSSAPI
DEBUG IMAP: AUTH: PLAIN
DEBUG: protocolConnect login, host=host.domain.com, user=user@domain.com,  password=<non-null>
A1 LOGIN user@domain.com password
A1 NO LOGIN failed.
DEBUG: trying to connect to host "host.domain.com", port 993, isSSL true
* OK The Microsoft Exchange IMAP4 service is ready.
A0 CAPABILITY
* CAPABILITY IMAP4 IMAP4rev1 AUTH=NTLM AUTH=GSSAPI AUTH=PLAIN UIDPLUS CHILDREN IDLE NAMESPACE LITERAL+
A0 OK CAPABILITY completed.
DEBUG IMAP: AUTH: NTLM
DEBUG IMAP: AUTH: GSSAPI
DEBUG IMAP: AUTH: PLAIN
DEBUG: protocolConnect login, host=host.domain.com, user=user@domain.com, password=<non-null>
A1 LOGIN user@domain.com password
A1 NO LOGIN failed.
javax.mail.AuthenticationFailedException: LOGIN failed.
at com.sun.mail.imap.IMAPStore.protocolConnect(IMAPStore.java:660)
at javax.mail.Service.connect(Service.java:317)
at javax.mail.Service.connect(Service.java:176)
at ConnectMail.connectMail(ConnectMail.java:63)
at Main.main(Main.java:9)

现在我收到了“NO LOGIN failed”异常。

这是我的完整代码:

Properties imapProps = new Properties();
imapProps.setProperty("mail.imaps.socketFactory.port", "993");
imapProps.setProperty("mail.imaps.starttls.enable", "true");
imapProps.setProperty("mail.imaps.socketFactory.class", "javax.net.ssl.SSLSocketFactory");
imapProps.setProperty("mail.imaps.socketFactory.fallback", "false");
imapProps.setProperty("mail.imaps.auth.plain.disable", "true");
imapProps.setProperty("mail.imaps.auth.ntlm.disable", "true");
imapProps.setProperty("mail.imaps.auth.gssapi.disable", "true");
imapProps.setProperty("username", "user@domain.com");   
imapProps.setProperty("password", "password");

String host = "host.domain.com";
int port = Integer.parseInt("993");

Authenticator authenticator = new Authenticator() {
    protected PasswordAuthentication getPasswordAuthentication() {
        return new PasswordAuthentication("user@domain.com", "password");
    }
};

session = Session.getInstance(imapProps, authenticator);

session.setDebug(true);

Store store = session.getStore("imaps");

store.connect(host, "user@domain.com", "password");

3 个答案:

答案 0 :(得分:2)

您需要使用支持NTLM身份验证的较新版本的JavaMail。最新版本为1.5.1

另请参阅此common mistakes列表。

答案 1 :(得分:1)

如果用户名和邮件ID相同,它将进行锻炼。

例如:系统用户名为john,邮件ID为john@test.com

IMAP尝试使用来自john@test.com的用户名“ john”登录邮件ID,如果用户ID不同则将无法登录。

答案 2 :(得分:0)

尝试使用您自己的身份验证器

public class ExchangeAuthenticator extends Authenticator {

    String username;
    String password;

    public ExchangeAuthenticator(String username, String password) {
        super();
        this.username= username;
        this.password= password;
    }

    public PasswordAuthentication getPasswordAuthentication() {
        return new PasswordAuthentication(username, password);
    }
}

并在您的代码中添加

session = Session.getInstance(props,new ExchangeAuthenticator(username, password));