这是我的选择查询:
select
b.S_SORT,
a.FABRIC1,
c.BRNCH_CODE,
a.XS_ALL,
a.S_ALL,
a.M_ALL,
a.L_ALL,
a.XL_ALL,
c.LABEL_CODE,
c.STATUS
from
jo_det as a
inner join
jo_hdr as c ON a.TRAN_NO = c.TRAN_NO
inner join
branch as b ON b.BRNCH_CODE = c.BRNCH_CODE
where
c.JO_NO = '1398'
ORDER BY B.S_SORT ASC
这就是结果:
如您所见,列 S_SORT 的排序工作正常。我想知道的是我如何安排 FABRIC1 的列10-2218-0110将是第一个,40-9515-0402将是每个BRNCH_CODE的最后一个。
从 S_SORT :1到3,FABRIC1的排列很好,但是在S_SORT:4中,第一个结构是40-9515-0402,最后一个结构是10-2218-0110。 / p>
有没有办法让我可以像S_SORT中的arrang一样订购FABRIC1:1到3?
答案 0 :(得分:1)
您只需将其添加到ORDER BY子句
中select
b.S_SORT,
a.FABRIC1,
c.BRNCH_CODE,
a.XS_ALL,
a.S_ALL,
a.M_ALL,
a.L_ALL,
a.XL_ALL,
c.LABEL_CODE,
c.STATUS
from
jo_det as a
inner join
jo_hdr as c ON a.TRAN_NO = c.TRAN_NO
inner join
branch as b ON b.BRNCH_CODE = c.BRNCH_CODE
where
c.JO_NO = '1398'
ORDER BY B.S_SORT ASC, FABRIC1 ASC
答案 1 :(得分:1)
您可以为 FABRIC1 再添加一个订单,如下所述:
select
b.S_SORT,
a.FABRIC1,
c.BRNCH_CODE,
a.XS_ALL,
a.S_ALL,
a.M_ALL,
a.L_ALL,
a.XL_ALL,
c.LABEL_CODE,
c.STATUS
from
jo_det as a
inner join
jo_hdr as c ON a.TRAN_NO = c.TRAN_NO
inner join
branch as b ON b.BRNCH_CODE = c.BRNCH_CODE
where
c.JO_NO = '1398'
ORDER BY
B.S_SORT ASC,
a.FABRIC1 ASC