Question

我正在尝试将twitter集成到android.I作为解析用户登录到twitter但无法更新我的状态，因为我现在收到禁用的403错误。这可能是403错误的原因以及如何纠正它？任何帮助将不胜感激.. 我的代码是

public void twitterbtnClick(View v)
{
    ParseTwitterUtils.logIn(this, new LogInCallback() {
        @Override
        public void done(ParseUser arg0, com.parse.ParseException arg1) {
            // TODO Auto-generated method stub
            if (arg0 == null) {
                  Log.d("MyApp", "Uh oh. The user cancelled the Twitter login.");
                } else if (arg0.isNew()) {
                  Log.d("MyApp", "User signed up and logged in through Twitter!");
                  TweetsTask task = new TweetsTask();
                  task.execute("Hi buddies");
                } else {
                  Log.d("MyApp", "User logged in through Twitter!");
                  TweetsTask task = new TweetsTask();
                  task.execute("Hi buddies");
                }
        }
        });

}
public class TweetsTask extends AsyncTask<String, Void, String> {

    @Override
    protected  String doInBackground(String... params) {
        // TODO Auto-generated method stub
        Log.d("Parameter",""+params[0]);


        HttpClient client =new DefaultHttpClient();
        String status = params[0];
        Log.d("Status",""+status);
        List<NameValuePair> parameters = new ArrayList<NameValuePair>();
        parameters.add(new BasicNameValuePair("mystring", status));
        Log.d("Parameter2",""+status);
        HttpPost httppost = new HttpPost("https://api.twitter.com/1.1/statuses/update.json");
        try {
            httppost.setEntity(new UrlEncodedFormEntity(parameters));
        } catch (UnsupportedEncodingException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } 

        ParseTwitterUtils.getTwitter().signRequest(httppost);
        try {
            HttpResponse response =   client.execute(httppost);
             if(response==null){
                 task="fail";

             }else{
                 task="success";

             }
        } catch (ClientProtocolException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } 
        return task;
    }

}
 protected void onPostExecute(String result) {
    if(task.equals("success"))
    {
         Toast.makeText(getApplicationContext(),"success",Toast.LENGTH_SHORT).show();
    }else{
         Toast.makeText( getApplicationContext()," error",Toast.LENGTH_SHORT).show();
    }
   }

Answer 1

我没有足够的声誉来评论user2853201的问题，而是通过查看代码。 NameValuePair参数＆＃34; mystring＆＃34;在代码中应更改为＆＃34; status＆＃34;。从Twitter文档中，＆＃34; 403＆＃34;当您尝试发送重复的推文时会发生错误。

以下是我使用Parse发送推文的方式：

这是我的twitter按钮的OnClickListener（）方法：

        btnTwitter.setOnClickListener(new OnClickListener(){
          public void onClick(View arg0) {
             ShareViaTwitter();

            }
         });

ShareViaTwitter（）方法：

 private void displayShareTwitter (){

 ParseTwitterUtils.logIn(this, new LogInCallback() {

    @Override
    public void done(ParseUser user, ParseException arg1) {
        // TODO Auto-generated method stub
           if (user == null) {
                  Log.d("MyApp", "Uh oh. The user cancelled the Twitter login.");
                } else if (user.isNew()) {
                  Log.d("MyApp", "User signed up and logged in through Twitter!");
                  new sendTweet().execute("your twitter status update");
                } else {
                  Log.d("MyApp", "User logged in through Twitter!");
                  new sendTweet().execute("your twitter status update");
                }

    }
    });


    }

sendTweet内部类：

 class sendTweet extends AsyncTask<String, Void, String> {

    boolean success = true; 
    @Override
    protected  String doInBackground(String... params) {
        try {
            HttpClient client = new DefaultHttpClient();
            String status = params[0];
            List<NameValuePair> parameters = new ArrayList<NameValuePair>();
            //This is where you add all the parameters you need for your tweet,
            //see "https://dev.twitter.com/docs/api/1/post/statuses/update" 
            //for all the optional parameters you can add here
            parameters.add(new BasicNameValuePair("status", status));
            HttpPost httppost = new HttpPost("https://api.twitter.com/1.1/statuses/update.json"); //API used here 1.1
            try {
                httppost.setEntity(new UrlEncodedFormEntity(parameters));
            } catch (UnsupportedEncodingException e) {
                success = false;
                    e.printStackTrace();
            } 

            ParseTwitterUtils.getTwitter().signRequest(httppost);//This seems to cause the app to ask for authorization each time I tweet
            HttpResponse response =   client.execute(httppost);             
        } catch (Exception e) {
            success = false; 
            e.printStackTrace();
        }
        return null;
    }

 protected void onPostExecute(String result) {

     if (success){
         Toast.makeText(getApplicationContext(),"sent tweet",Toast.LENGTH_SHORT).show();
     }else{
         Toast.makeText(getApplicationContext(),"tweet failed",Toast.LENGTH_SHORT).show();
     }


   }

}

在android上更新twitter上的状态

1 个答案: