Question

我很难把所有事情搞清楚。这个问题来自这个问题，Inserting into a Table joined to another Table by a reference table?。

我想要做的事情的一半是在这个问题中解释的，我试图做的其他一些事情将在这个问题中解释。

我在Teams表中有这些数据（也可以是Projects表）和Members表

+---------+---------------------+----------------------+
| team_id | team_name           | team_desc            |
+---------+---------------------+----------------------+
|       1 | Toronto Maple Leafs | Team is Awesome!     |
|       2 | Vancouver Kanucks   | Team Sucks!          |
|       3 | Chicago Bulls       | Team is Fine!        |
|       4 | New York Boys       | Nah! It doesn't suck |
+---------+---------------------+----------------------+

和成员表中的这些数据

+-----------+-----------+----------+---------------------------------+---------------+-------------+-------------------------------+------------+------------+-------------+----------+-----------------+
| member_id | firstname | lastname | address                         | state         | country     | email                         | phone      | experience | designation | username | password        |
+-----------+-----------+----------+---------------------------------+---------------+-------------+-------------------------------+------------+------------+-------------+----------+-----------------+
|         1 | Duncan    | Daniel   | P.O. Box 470, 2775 Ac Road      | NS            | Israel      | duncan@aol.in                 | 9288091790 | 1          | Script      | duncan   | debbyisaweseome |
|         2 | Ivan      | Richmond | P.O. Box 797, 906 Cursus Street | New Brunswick | Timor-Leste | ligula.tortor.dictum@Duis.com | 8087179788 | 5          | Storyboard  | ivan     | ivaniscool      |
+-----------+-----------+----------+---------------------------------+---------------+-------------+-------------------------------+------------+------------+-------------+----------+-----------------+

这两个表由这个teams_members表连接，

+------------------+---------+------+-----+---------+----------------+
| Field            | Type    | Null | Key | Default | Extra          |
+------------------+---------+------+-----+---------+----------------+
| teams_members_id | int(11) | NO   | PRI | NULL    | auto_increment |
| teams_id         | int(11) | NO   | MUL | NULL    |                |
| members_id       | int(11) | NO   | MUL | NULL    |                |
+------------------+---------+------+-----+---------+----------------+

正如您所见teams_id＆amp; members_id是来自团队的外键和成员。

现在正如上面提到的问题中的upvoted帖子中所建议的那样，我首先在团队中插入一行，然后在这样的team_members表中插入，

INSERT INTO teams(`team_name`,`team_desc`) values ("New York Boys", "Nah! It doesn't suck");
INSERT INTO teams_members (`members_id`,`teams_id`) VALUES
((SELECT member_id from members WHERE member_id = 2),
(SELECT team_id from teams WHERE team_name = "New York Boys"))

然后尝试选择由此类特定成员创建的团队

SELECT * FROM teams_members, members, teams WHERE members_id = member_id && member_id = 1;

但它没有只显示一个团队，而是给了我这个结果：

+------------------+----------+------------+-----------+-----------+----------+----------------------------+-------+---------+---------------+------------+------------+-------------+----------+-----------------+---------+---------------------+----------------------+
| teams_members_id | teams_id | members_id | member_id | firstname | lastname | address                    | state | country | email         | phone      | experience | designation | username | password        | team_id | team_name           | team_desc            |
+------------------+----------+------------+-----------+-----------+----------+----------------------------+-------+---------+---------------+------------+------------+-------------+----------+-----------------+---------+---------------------+----------------------+
|                1 |        3 |          1 |         1 | Duncan    | Daniel   | P.O. Box 470, 2775 Ac Road | NS    | Israel  | duncan@aol.in | 9288091790 | 1          | Script      | duncan   | debbyisaweseome |       1 | Toronto Maple Leafs | Team is Awesome!     |
|                1 |        3 |          1 |         1 | Duncan    | Daniel   | P.O. Box 470, 2775 Ac Road | NS    | Israel  | duncan@aol.in | 9288091790 | 1          | Script      | duncan   | debbyisaweseome |       2 | Vancouver Kanucks   | Team Sucks!          |
|                1 |        3 |          1 |         1 | Duncan    | Daniel   | P.O. Box 470, 2775 Ac Road | NS    | Israel  | duncan@aol.in | 9288091790 | 1          | Script      | duncan   | debbyisaweseome |       3 | Chicago Bulls       | Team is Fine!        |
|                1 |        3 |          1 |         1 | Duncan    | Daniel   | P.O. Box 470, 2775 Ac Road | NS    | Israel  | duncan@aol.in | 9288091790 | 1          | Script      | duncan   | debbyisaweseome |       4 | New York Boys       | Nah! It doesn't suck |
+------------------+----------+------------+-----------+-----------+----------+----------------------------+-------+---------+---------------+------------+------------+-------------+----------+-----------------+---------+---------------------+----------------------+

我的查询中是否缺少某些内容？此外，关于插入部分，还有更好的方法吗？

Answer 1

SELECT * 
FROM teams_members tm, members m, teams t 
WHERE tm.members_id = m.member_id 
AND m.member_id = 1
AND tm.teams_id = t.team_id

Answer 2

1）将*替换为您想要获取的列。

2）为表添加别名：... FROM teams_members tm，members m，teams t where ...

3）在其中使用带别名表的字段：m.member_id = tm.member_id

Answer 3

您需要使用加入来获取团队名称。

SELECT查询需要看起来像这样....

＆＃34; SELECT team_name FROM teams JOIN teams_members ON teams.teams_id = teams_members.teams_id＆＃34;

从team表中获取所有行数据使用此查询

＆＃34; SELECT * FROM团队JOIN teams_members ON teams.teams_id = teams_members.teams_id＆＃34;

从参考表连接的两个表中选择？

3 个答案: