我希望在我的代码中获得像http://printio.ru/
这样的撤销/重做功能,如何为我的画布编写撤消/重做。
我在我的代码中尝试了http://jsfiddle.net/SpgGV/27/但它不能完美地工作,1步撤消重做也会有效。
有什么建议吗?
var canvas = new fabric.Canvas('c');
var hw=[];
var x=0;
var current;
var list = [];
var state = [];
var index = 0;
var index2 = 0;
var action = false;
var refresh = true;
state[0] = JSON.stringify(canvas.toDatalessJSON());
console.log(JSON.stringify(canvas.toDatalessJSON()));
$("#clear").click(function(){
canvas.clear();
index=0;
});
$("#addtext").click(function(){
++index;
action=true;
hw[x] = new fabric.Text('Sample', {
fontFamily: 'Hoefler Text',
left: 100,
top: 100,
//textAlign: 'center',
fill: 'navy',
});
canvas.add(hw[x]);
x++;
});
canvas.on("object:added", function (e) {
if(action===true){
var object = e.target;
console.log(JSON.stringify(canvas.toDatalessJSON()));
state[index] = JSON.stringify(canvas.toDatalessJSON());
refresh = true;
action=false;
canvas.renderAll();
}
});
function undo() {
if (index < 0) {
index = 0;
canvas.loadFromJSON(state[index]);
canvas.renderAll();
return;
}
console.log('undo');
canvas.loadFromJSON(state[index]);
console.log(JSON.stringify(canvas.toDatalessJSON()));
canvas.renderAll();
action = false;
}
function redo() {
action = false;
if (index >= state.length - 1) {
canvas.loadFromJSON(state[index]);
canvas.renderAll();
return;
}
console.log('redo');
canvas.loadFromJSON(state[index]);
console.log(JSON.stringify(canvas.toDatalessJSON()));
canvas.renderAll();
canvas.renderAll();
}
canvas.on("object:modified", function (e) {
var object = e.target;
console.log('object:modified');
console.log(JSON.stringify(canvas.toDatalessJSON()));
state[++index] = JSON.stringify(canvas.toDatalessJSON());
action=false;
});
$('#undo').click(function () {
index--;
undo();
});
$('#redo').click(function () {
index++;
redo();
});