Question

我想要一个可以使用mysqli_fetch_assoc（）获取的函数，它是这样的：

<?php
$con = mysqli_connect("localhost", "root", "", "primary");
function fetchAssoc($query){
    global $con;
    $queryexec = mysqli_query($con, $query);
    $return = array();
    while($stuff = mysqli_fetch_assoc($queryexec)){
        $return[] = $stuff;
    }
    return $return;
}
$yup = fetchAssoc("SELECT * FROM posts");
while($thing = $yup){
    echo $thing, "<br />";
}
?>

但由于某种原因，我得到了这个结果：注意：第20行的C：\ xampp \ htdocs \ Experiments \ index.php中的数组到字符串转换阵列

第20行是echo $thing, "<br />";

Answer 1

$yup = fetchAssoc("SELECT * FROM posts");
while($thing = $yup){
    echo $thing, "<br />";
}

$yup是关联数组，在你的while循环中，你分配给$thing - 现在也是一个数组

您应该执行类似

的操作

foreach($yup as $y){

  // here $y is an array in the form of 
  // array( ['column_name'] => 'value', '[other_col]' => 'value')
  // so you could do 
  echo $y['column'], $y['other_col'],'<br />';

}

Answer 2

fetch_assoc会返回一系列项目，一次打印出来（看看有什么）你可以这样做：

print_r($thing);

或者如果你想单独打印它们：

foreach($thing as $t){
  echo $t . '<br />';
}

此外，while循环将永远运行，因为它基本上是这样的：

while(true){
    // do something
}

Answer 3

<?php
$con = mysqli_connect("localhost", "root", "", "primary");
function fetchAssoc($query){
global $con;
$queryexec = mysqli_query($con, $query);
$return = array();
while($stuff = mysqli_fetch_assoc($queryexec)){
    $return[] = $stuff;
}
return $return;
}
$yup = fetchAssoc("SELECT * FROM posts");
foreach($yup AS $thing){
 // $thing is an associative array so use keys to access data from it like
  echo $thing['ID'], "<br />";
}
?>

Answer 4

你可以尝试这个程序。

<?php
$con = mysqli_connect("localhost", "root", "", "primary");
function fetchAssoc($query){
    global $con;
    $queryexec = mysqli_query($con, $query);
    $return = array();
    while($stuff = mysqli_fetch_assoc($queryexec)){
        $return[] .= $stuff['name'];  //Enter your column name in place of name from your posts table.
    }
    return $return;
}
$yup = fetchAssoc("SELECT * FROM posts");

foreach($yup as $thing){
    echo $thing . "<br />";
}
?>

由于

Answer 5

$con = mysqli_connect("localhost", "root", "", "primary");
function fetchAssoc($query){
    global $con;
    $queryexec = mysqli_query($con, $query);
    $return = array();
    while($stuff = mysqli_fetch_assoc($queryexec)){
        $return[] = $stuff;
    }
    return $return;
}
$yup = fetchAssoc("SELECT * FROM posts");
foreach($yup as $thing){
    foreach($thing as $element){
        echo $element."<br/>";
    }
}

Answer 6

您的代码非常完美。但只是一个错误。这里$ thing是一个数组，所以你无法回应它。试试这个：

while($thing = $yup){
   print_r ($thing);
   echo  "<br />";
}

函数中的mysqli_fetch_assoc

6 个答案: