Question

我正在写一个sp。我的要求如下：

表A：

我是主键。

+----+---------+
| Id |  Col1   |
+----+---------+
|  1 | Sample1 |
|  2 | Sample2 |
+----+---------+

表B：

Id是主键。 Col1_Id是TableA的外键

+----+---------+-------+
| Id | Col1_Id | Col2  |
+----+---------+-------+
|  1 |       1 | TestA |
|  2 |       1 | TestB |
|  3 |       2 | TestC |
+----+---------+-------+

表C：

我是主键。

+----+------------------------+
| Id |     QusetionText       |
+----+------------------------+
|  1 | Sample Question One?   |
|  2 | Sample Question Two?   |
|  3 | Sample Euestion Three? |
+----+------------------------+

我的输出应该是; 提出：

Id是主键。 Col1_Id是TableA的外键 Col2_Id是TableB的外键

+----+------------+---------+---------+------------------------+
| Id | QuestionId | Col1_Id | Col2_Id |      QusetionText      |
+----+------------+---------+---------+------------------------+
|  1 | Q_2013     |       1 |       1 | Sample Question One?   |
|  2 | Q_2013     |       1 |       1 | Sample Question Two?   |
|  3 | Q_2013     |       1 |       1 | Sample Question Three? |
|  4 | Q_2013     |       1 |       2 | Sample Question One?   |
|  5 | Q_2013     |       1 |       2 | Sample Question Two?   |
|  6 | Q_2013     |       1 |       2 | Sample Question Three? |
|  7 | Q_2013     |       2 |       3 | Sample Question One?   |
|  8 | Q_2013     |       2 |       3 | Sample Question Two?   |
|  9 | Q_2013     |       2 |       3 | Sample Question Three? |
+----+------------+---------+---------+------------------------+

请告诉我如何编写查询以获取TableD。

提前感谢大家的回复。

Answer 1

检查一下，

SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
-- =============================================
-- Author:      Prathiba
-- Create date: 
-- Description: 
-- =============================================
 CREATE PROCEDURE SampleProc 

 AS
 BEGIN
SET NOCOUNT ON;
           SELECT dbo.TableA.Id, dbo.TableB.Col1_Id, dbo.TableC.Id AS Col2_Id, dbo.TableC.QuestionText
           FROM   dbo.TableA INNER JOIN
                  dbo.TableB ON dbo.TableA.Id = dbo.TableB.Col1_Id CROSS JOIN
                  dbo.TableC
 END
 GO

请确保与您的 TableC 没有任何关系，即为什么交叉加入正在使用。

如何编写存储过程

1 个答案: