Question

在这种情况下我需要更多的帮助，做一些类似于两种模式之间的grep：我需要寻找Everyone Allow FullControl

说我有这个：

    Path   : Microsoft.PowerShell.Core\FileSystem::\\eiesc1\Service_Legal 
    Access : BUILTIN\Administrators Allow  FullControl
    -----------------------
    Path   : Microsoft.PowerShell.Core\FileSystem::\\eiesc1\balco 
    Access : Everyone Allow  268435456
             Everyone Allow  FullControl
    -----------------------
    Path   : Microsoft.PowerShell.Core\FileSystem::\\eiesc1\BCDRPlanning 
    Access : Everyone Allow  FullControl
             Everyone Allow  268435456
    -----------------------

所以我会得到类似的东西：

    Path   : Microsoft.PowerShell.Core\FileSystem::\\eiesc1\balco 
             Everyone Allow  FullControl
    -----------------------
    Path   : Microsoft.PowerShell.Core\FileSystem::\\eiesc1\BCDRPlanning 
    Access : Everyone Allow  FullControl

我不知道该怎么做所以我来这里

Answer 1

尝试使用sed

sed -nr '/-{3,}/h; /Path\s*:/H; /Everyone\s+Allow\s+FullControl/{x;G;p}' file

输出：

    -----------------------
    Path   : Microsoft.PowerShell.Core\FileSystem::\\eiesc1\balco
             Everyone Allow  FullControl
    -----------------------
    Path   : Microsoft.PowerShell.Core\FileSystem::\\eiesc1\BCDRPlanning
    Access : Everyone Allow  FullControl

简短说明

sed -nr '
    /-{3,}/h;            # if '---' pattern is found in a line, copy it to hold space
    /Path\s*:/H;         # if 'Path  :' pattern is found in a line, append it to hold space
    /Everyone\s+Allow\s+FullControl/{x;G;p}    # if 'Everyone Allow  FullControl' pattern is found in a line, 1) exchange Pattern and Hold space, 2) Append pattern space to hold space and 3) print pattern space.
' file

这里我们使用sed

的模式空间和保持空间操纵器

来自man sed

的代码段

   h H    Copy/append pattern space to hold space.   
   g G    Copy/append hold space to pattern space.
   x      Exchange the contents of the hold and pattern spaces.

Answer 2

您可以使用awk

执行此类操作

awk '/Everyone Allow/ && /FullControl/' RS="-" file

    Path   : Microsoft.PowerShell.Core\FileSystem::\\eiesc1\balco
    Access : Everyone Allow  268435456
             Everyone Allow  FullControl


    Path   : Microsoft.PowerShell.Core\FileSystem::\\eiesc1\BCDRPlanning
    Access : Everyone Allow  FullControl
             Everyone Allow  268435456

恢复分隔符：

awk '/Everyone Allow/ && /FullControl/' RS="-" file | awk '/[0-9]+/ && /Everyone/ {next} $0=="" {$0="-----------------------"}1'
-----------------------
    Path   : Microsoft.PowerShell.Core\FileSystem::\\eiesc1\balco
             Everyone Allow  FullControl

-----------------------
    Path   : Microsoft.PowerShell.Core\FileSystem::\\eiesc1\BCDRPlanning
    Access : Everyone Allow  FullControl

两个模式之间的awk / sed grep并获得它们之间的内容，这可能吗？

2 个答案: