Question

我有代码：

// entity
public class PermissInfo
{
    public int PermissValue { get; set; }
}

// used class
public class MenuPermiss
{
    public static readonly PermissInfo PermissView = new PermissInfo { PermissValue = 1 };
    public static readonly PermissInfo PermissEdit = new PermissInfo { PermissValue = 2 };
    public static readonly PermissInfo PermissDelete = new PermissInfo { PermissValue = 4 };
}

并实现如下代码：

// implement class: check permiss
public static class ImplementClass
{
    // used like: return CheckPermiss(MenuPermiss.PermissEdit);
    public static bool CheckPermiss(PermissInfo permiss)
    {
        // How to get "MenuPermiss" class info by "permiss" param

        return false;
    }
}

如何通过MenuPermiss.PermissEdit param获取MenuPermiss CLASS？

Answer 1

使用这种语法是不可能的：

ImplementClass.DoSomething(MyClass.MyProperty);

但可能有这个：

ImplementClass.DoSomething(() => MyClass.MyProperty);

解决方案：

using System.Linq.Expressions;

public static class ImplementClass
{
    public static bool DoSomething<T>(Expression<Func<T>> propertyExpression)
    {
        var memberInfo = ((MemberExpression)propertyExpression.Body).Member;
        var declaringType = memberInfo.DeclaringType;

        Console.WriteLine(declaringType.Name); // outputs "MyClass"

        return false;
    }
}

Answer 2

链接参考here：

它的语法很好用：

PermissHelper.CheckPermiss(()=>MenuPermiss.PermissDelete)

我尝试使用此代码实现，并返回“＆lt;＆gt; c__DisplayClass0”值。如何解决？

PermissHelper.CheckPermiss(MenuPermiss.PermissDelete)

和

public static string CheckPermiss(PermissInfo permissInfo)
{
    Expression<Func<PermissInfo>> x = () => permissInfo;

    var memberInfo = ((MemberExpression)x.Body).Member;
    var declaringType = memberInfo.DeclaringType;

    return declaringType != null ? declaringType.Name : "";
}

如何通过带有/ reflection C＃的属性获取类信息

2 个答案: