Question

我试图将两个日期之间的差异分成SQL Server 2005中的int。我收到错误 -

Msg 156, Level 15, State 1, Line 5
Incorrect syntax near the keyword 'SELECT'.

SQL -

DECLARE @id varchar(10)
DECLARE @diff int

SET @id = 'D5234'
SET @diff = SELECT DATEDIFF(minute, [PROC].[START_DATE], [PROC].[END_DATE]) 
FROM [PROCESSES] AS [PROC]
WHERE [PROC].[ID] = @id

我该如何解决？

Answer 1

您需要使用：

SELECT @diff = DATEDIFF(minute, [PROC].[START_DATE], [PROC].[END_DATE]) 
FROM [PROCESSES] AS [PROC]
WHERE [PROC].[ID] = @id;

或者

SET @diff = (SELECT DATEDIFF(minute, [PROC].[START_DATE], [PROC].[END_DATE]) 
            FROM [PROCESSES] AS [PROC]
            WHERE [PROC].[ID] = @id);

（用括号中的select语句）。

如果您有多个行匹配，前者只会将@diff设置为遇到的最后一行，如果您有多行，后者将失败。

需要将日期差异存储到int中

1 个答案: