Question

我有一个面板代码窗格，显示此代码以显示/隐藏内容，如果一个字段，它工作得很好但我希望代码只是在％node中没有内容时显示任何内容：field_desc6

<script language="javascript">
function toggle() {
    var ele = document.getElementById("toggleText");
    var text = document.getElementById("displayText");
    if(ele.style.display == "block") {
            ele.style.display = "none";
        text.innerHTML = "Show Non-CGD Publications";
    }
    else {
        ele.style.display = "block";
        text.innerHTML = "Hide Non-CGD Publications";
    }
}
</script>


<a id="displayText" href="javascript:toggle();">Show Non-CGD Publications</a>
<div id="toggleText" style="display: none">%node:field_desc6</div>

Answer 1

试试这个：

<script language="javascript">
function toggle() {
    var ele = document.getElementById("toggleText");
    var text = document.getElementById("displayText");
    if(ele.style.display == "block") {
            ele.style.display = "none";
        text.innerHTML = "Show Non-CGD Publications";
    }
    else {
        ele.style.display = "block";
        text.innerHTML = ""; // here you don't put any text...
    }
}
</script>


<a id="displayText" href="javascript:toggle();">Show Non-CGD Publications</a>
<div id="toggleText" style="display: none">%node:field_desc6</div>

Drupal 7中的条件字段

1 个答案: