Question

我的代码有什么问题

    SQL> declare
  2  mark number :=50;
  3  begin
  4  mark :=& mark;
  5  if (mark between 85 and 100)
  6  then
  7  dbms_output.put_line('mark is A ');
  8  else if (mark between 50 and 65) then
  9  dbms_output.put_line('mark is D ');
 10  else if (mark between 66 and 75) then
 11  dbms_output.put_line('mark is C ');
 12  else if (mark between 76 and 84) then
 13  dbms_output.put_line('mark is B');
 14  else 
 15  dbms_output.put_line('mark is F');
 16  end if;
 17  end;
 18  /
Enter value for mark: 65
old   4: mark :=& mark;
new   4: mark :=65;
end;
   *

第17行的错误： ORA-06550：第17行，第4栏： PLS-00103：遇到符号＆＃34;;＆＃34;当期待以下之一时：如果

Answer 1

问题是 else 和 if 是这里的两个运算符。由于你打开一个新的'if'，你需要一个相应的'end if'。

因此：

declare
mark number :=50;
begin
  mark :=& mark;
  if (mark between 85 and 100) then
    dbms_output.put_line('mark is A ');
  else 
    if (mark between 50 and 65) then
      dbms_output.put_line('mark is D ');
    else 
      if (mark between 66 and 75) then
        dbms_output.put_line('mark is C ');
      else 
        if (mark between 76 and 84) then
          dbms_output.put_line('mark is B');
        else 
          dbms_output.put_line('mark is F');
        end if;
      end if;
    end if;
  end if;
end;
/

或者你可以使用elsif：

declare
mark number :=50;
begin
  mark :=& mark;
  if (mark between 85 and 100)
    then
    dbms_output.put_line('mark is A ');
  elsif (mark between 50 and 65) then
    dbms_output.put_line('mark is D ');
  elsif (mark between 66 and 75) then
    dbms_output.put_line('mark is C ');
  elsif (mark between 76 and 84) then
    dbms_output.put_line('mark is B');
  else 
    dbms_output.put_line('mark is F');
  end if;
end;
/

Answer 2

IF语句在PL/SQL中包含以下形式：

IF THEN

IF THEN ELSE

IF THEN ELSIF

您使用了elseif，这在PL / SQL方面是错误的。需要将其替换为ELSIF。

DECLARE
  mark NUMBER :=50;
BEGIN
  mark :=& mark;
  IF (mark BETWEEN 85 AND 100) THEN
    dbms_output.put_line('mark is A ');
  elsif (mark BETWEEN 50 AND 65) THEN
    dbms_output.put_line('mark is D ');
  elsif (mark BETWEEN 66 AND 75) THEN
    dbms_output.put_line('mark is C ');
  elsif (mark BETWEEN 76 AND 84) THEN
    dbms_output.put_line('mark is B');
  ELSE
    dbms_output.put_line('mark is F');
  END IF;
END;
/

PLS-00103：遇到符号“;”当期待以下之一时：

2 个答案: