Question

我正在尝试为类项目创建一个简单的tic-tac-toe游戏，但我不确定如何完成剩下的代码。我真的很感激任何见解或输入，我将如何完成剩下的这一切。该代码目前在技术上有效，但它所做的只是显示一块充满none和“游戏是平局的”。

PLAYERS = ["X", "O"]

def display_board(board):
        print board[0][0:3]
        print board[1][0:3]
        print board[2][0:3]

def create_empty_board():
        return [[None, None, None], [None, None, None], [None, None, None]]

def board_is_full(board):
        for row in board:
                if None not in board:
                        return True


def winner(board):
        if board[0][0] == board[0][1] == board[0][2] != None:
                return board[0][0]
        elif board[1][0] == board[1][1] == board[1][2] != None:
                return board[1][0]
        elif board[2][0] == board[2][1] == board[2][2] != None:
                return board[2][0]
        elif board[0][0] == board[1][0] == board[2][0] != None:
                return board[0][0]
        elif board[0][1] == board[1][1] == board[2][1] != None:
                return board[0][1]
        elif board[0][2] == board[1][2] == board[2][2] != None:
                return board[0][2]
        elif board[0][0] == board[1][1] == board[2][2] != None:
                return board[0][0]
        else:
                return None

def game_over(board):
        if board_is_full(board) == True:
                return True
def player_turn(board, playerid):
    """ Ask the player to select a coordinates for their next move. The player needs to select a row and a column. If the coordinates the player selects are outside of the board, or are already occupied, they need to be prompted to select coordinates again, until their input is valid."""
    return 1, 1 # by default, return row 1, column 1 as the player's desired location on the board; you need to implement this

def play():
    """ This is the main function that implements a hot seat version of Tic Tac Toe."""
    # the code below is just an example of how you could structure your play() function
    # if you implement all the functions above correctly, this function will work
    # however, feel free to change it if you want to organize your code differently
    board = create_empty_board()
    display_board(board)
    current_player = 0
    while not game_over(board):
        board = player_turn(board, PLAYERS[current_player])
        current_player = (current_player + 1) % len(PLAYERS)
        display_board(board)
    who_won = winner(board)
    if who_won is None:
        print "The game was a tie."
    else:
        print "The winning player is", who_won

if __name__ == "__main__":
    play()

Answer 1

您的第一个问题是您的board_is_full错了。对于每一行，而不是检查您是否正在检查None not in board。这总是如此; board是三个列表的列表，因此None永远不会出现在其中。你想检查每一行，而不是整个板。但只有if None not in row不是正确的 - 只要任何行已满，就会成立，而不是所有行。所以当你找到一个非完整的行时你想要返回False，如果你没有找到任何行，你想要返回True。你应该能够自己做到这一点。

您的下一个问题是您尚未实施player_turn。对于真正的hacky实现，您可以使用return input('row, col: ')。除非你能理解为什么这样有效，否则你不应该把它作为你的作业（如果你理解它为什么有效，你就不想使用它）。此外，它不是非常用户友好 - 它不会告诉你轮到它，或者向你展示董事会或其他什么。你将这些东西作为参数，这样你就可以使用它们。无论如何，单线程足以让你现在接下来的问题，所以你可以稍后再回来。

您的下一个问题是player_turn会返回一对数字，而您只是将这对数字分配给board。你不能这样做。你想要的是这样的：

row, col = player_turn(board, PLAYERS[current_player])
board[row][col] = PLAYERS[current_player]

即使有人已经赢了，游戏也会让你继续玩，直到董事会满员为止。但实际上，如果董事会已满，你想完成，或那里是胜利者。（事实上，理想情况下，你想在胜利不可能的时候尽快完成，但这有点复杂。你可以通过将前一句翻译成while的替代来做一件简单的事情。语句。）

这应该让你找到任何其他小错误，写一个正确的player_turn函数，寻找简化现有代码的方法等等。

简单的Tic-Tac-Toe在python 2.7中

1 个答案: