如何使函数支持此
的参数 public List<string> getfiles(string FTPhostname, string FTPpath,string FTPusername,string FTPpassword,string extension)
{
'request to ftp hostname
'get response from
'list all directories and files
'search for spesified extension files
}
任何方式吗?
答案 0 :(得分:1)
这里是一个返回List
的函数的解决方案 public List<string> getfiles(string FTPhostname, string FTPpath,string FTPusername,string FTPpassword,string extension)
{
FtpWebRequest ftpRequest = (FtpWebRequest)WebRequest.Create("ftp://" + FTPhostname + "/" + FTPpath );
ftpRequest.Credentials = new NetworkCredential(FTPusername , FTPpassword );
ftpRequest.Method = WebRequestMethods.Ftp.ListDirectory;
FtpWebResponse response = (FtpWebResponse)ftpRequest.GetResponse();
StreamReader streamReader = new StreamReader(response.GetResponseStream());
List<string> results = new List<string>();
string line = streamReader.ReadLine();
while (!string.IsNullOrEmpty(line))
{
if (line.Contains(extension)) {
line = streamReader.ReadLine();
results.Add(line);}
else {line = streamReader.ReadLine(); }
}
streamReader.Close();
return results;
}
然后为ex:png
文件
String[] txtfounds= getfiles("ftp.piacton.com", "/Public/Software/Official/LightField/Archives/", "anonymous", "k3tnel31@k.com", ".png").ToArray();
如果要将此结果添加到lisbox:
listBox1.DataSource = txtfounds;
答案 1 :(得分:0)
有错误,您需要执行
results.Add(line);
之前打电话给
results.Add(line);
获取正确的文件。