Question

我正在尝试使用Selenium。问题如下：

文档结构：

<div class="jsSkills oSkills">
 <a class="oTag oTagSmall oSkill" href="/contractors/skill/software-testing/" data-contractor="749244">software-testing</a>
 <a class="oTag oTagSmall oSkill" href="/contractors/skill/software-qa-testing/" data-contractor="749244">software-qa-testing</a>
 <a class="oTag oTagSmall oSkill" href="/contractors/skill/blog-writing/" data-contractor="749244">blog-writing</a>
</div>

我需要获取所有a的文本，如下所示：

{"software-testing", "software-qa-testing", "blog-writing"}

我试过了：

contrSkill = driver.find_element(:xpath, "//div[contains(@class, 'jsSkills')]").text
puts contrSkill

但得到了这个：

"software-testingsoftware-qa-testingblog-writing"

请解释如何正确制作阵列。

Answer 1

您应该获得所需的所有链接元素（使用find_elements）。然后你可以迭代每个链接并将其文本收集到一个数组中（Ruby有一个collect方法可以帮助解决这个问题。）

# Get all of the link elements within the div
skill_links = driver.find_elements(:xpath, "//div[contains(@class, 'jsSkills')]/a")

# Create an array of the text of each link
skill_text_array = skill_links.collect(&:text)
p skill_text_array
#=> ["software-testing", "software-qa-testing", "blog-writing"]

将Xpath元素的文本放入数组

1 个答案: