Question

我这样打电话：

HttpWebResponse response = (HttpWebResponse)request.GetResponse();
using (var reader = new StreamReader(response.GetResponseStream()))
{
    var line = reader.ReadLine();
}

“行”内容是：

<?xml version="1.0" encoding="UTF-8"?>
<soap:Envelope xmlns:soap="...." xmlns:xsd="..." xmlns:xsi=".....">
   <soap:Body>
      <findResponse xmlns="....">
         <out>
            <MyType>
               <city>CityA</city>
               <firstName>AAA</firstName>
               <lastName>A</lastName>
            </MyType>
            <MyType>
               <city>CityB</city>
               <firstName>BBB</firstName>
               <lastName>B</lastName>
            </MyType>       
         </out>
      </findResponse>
   </soap:Body>
</soap:Envelope>

public class MyType
{
    public string FirstName { get; set; }
    public string LastName { get; set; }
    public string City { get; set; }
}

我想返回一个List，在这种情况下有两个条目。

我该怎么做？

谢谢，

Answer 1

这样的事情怎么样：

var list = XDocument.Load(response.GetResponseStream())
    .Descendants("MyType")
    .Select(elem => new MyType
    {
        FirstName = elem.Element("firstName").Value,
        LastName = elem.Element("lastName").Value,
        City = elem.Element("city").Value
    }).ToList();

另外，HttpWebResponse实现IDisposable并且应该放在using内。因此整个命令可能如下所示：

using (HttpWebResponse response = (HttpWebResponse)request.GetResponse())
{
    var list = XDocument.Load(response.GetResponseStream())
        .Descendants("MyType")
        .Select(elem => new MyType
        {
            FirstName = elem.Element("firstName").Value,
            LastName = elem.Element("lastName").Value,
            City = elem.Element("city").Value
        }).ToList();
}

更新：这可能是命名空间问题：

XNamespace ns = "http://www.your-namespace.com";
var list = XDocument.Load(response.GetResponseStream())
    .Descendants(ns + "MyType")
    .Select(elem => new MyType
    {
        FirstName = elem.Element("firstName").Value,
        LastName = elem.Element("lastName").Value,
        City = elem.Element("city").Value
    }).ToList();

Answer 2

从你的“line”创建一个xml，其中out标记为root，然后将其转换为json，然后将json反序列化为List：

var myListOfMyType = JsonConvert.DeserializeObject(myJson, typeof(MyType));

将StreamReader转换为对象列表

2 个答案: