检查可变参数模板声明中的参数类型

时间:2013-11-18 10:36:03

标签: c++ templates variadic

我得到了一个简单的可变参数模板声明,就像经典的一样:

template <typename... Arguments>
class VariadicTemplate;

我需要实现的是让VariadicTemplate类执行某些类型检查;可变参数模板应以某种迭代形式检查收到的所有参数应该说明类型<Foo>

我在某个地方看到了类似的东西,但现在我无法辨认它在哪里:P

3 个答案:

答案 0 :(得分:6)

struct Foo {};

#include <type_traits>

template<class T, class...>
struct are_same : std::true_type
{};

template<class T, class U, class... TT>
struct are_same<T, U, TT...>
    : std::integral_constant<bool, std::is_same<T,U>{} && are_same<T, TT...>{}>
{};

template<typename... Arguments>
class VariadicTemplate
{
    static_assert(are_same<Foo, Arguments...>{}, "a meaningful error message");
};

int main()
{
    VariadicTemplate<Foo, Foo, Foo, Foo> v0{}; (void)v0;
    VariadicTemplate<Foo, int, Foo, double> v1{}; (void)v1;
}

但是有些东西告诉我你想知道参数是否是类模板Foo的所有特化:

template<class T, class U>
struct Foo {};

#include <type_traits>

template<template<class...> class T, class U>
struct is_template_of
{
    template<class... TT>
    static std::true_type test(T<TT...>*);

    static std::false_type test(...);

    constexpr static bool value = decltype(test((U*)nullptr)){};
};

template<template<class...> class T, class...>
struct is_template_of_N : std::true_type
{};

template<template<class...> class T, class U, class... TT>
struct is_template_of_N<T, U, TT...>
    : std::integral_constant<bool,    is_template_of<T,U>::value
                                   && is_template_of_N<T, TT...>{}>
{};

template<typename... Arguments>
class VariadicTemplate
{
    static_assert(is_template_of_N<Foo, Arguments...>{},
                  "a meaningful error message");
};

int main()
{
    VariadicTemplate<Foo<int, double>, Foo<int, int>> v0; (void)v0;
    VariadicTemplate<Foo<int, double>, int> v1; (void)v1;
}

答案 1 :(得分:2)

这里有另一种解决方案:P

这是:

template <bool... b> struct static_all_of;

// do recursion if the first argument is true
template <bool... tail>
struct static_all_of<true, tail...> : static_all_of<tail...> {};

// end recursion if first argument is false
template <bool... tail>
struct static_all_of<false, tail...> : std::false_type {};

// end recursion if no more arguments need to be processed
template <> struct static_all_of<> : std::true_type {};


// First template argument is given as the type checking for the is_base_of() function

template <typename Type, typename... Requirements>
class CollectionOfCommonBase : public Requirements...
{
  static_assert(static_all_of<std::is_base_of<Type, Requirements>::value...>::value, "One or more template arguments are not base_of the one specified - given template specialization is not allowed.");
};

所以你得到它的工作:

class Foo {};

class AFoo : public Foo {};
class BFoo : public Foo {};

class MyCollection : public CollectionOfCommonBase<Foo, AFoo, BFoo> {};

答案 2 :(得分:0)

如果要检查类型(不询问基本类型):

template <typename ... Foos>
void Foo (Foos ... foos)
{
    static_assert(are_same_v<int, Foos...>);
}

处理示例问题:

class _MytimeoffState extends State<Mytimeoff> {

  List<Map> list = [];

  void getList() async {
    var data = await http
        .get('https://my-json-server.typicode.com/darshanaAlex/db2/time_off');
    var jsonData = json.decode(data.body);

    setState(() {
      for (Map js in jsonData) {
        list.add(js);
      }
    });
    print(jsonData);
  }

  @override
  void initState() {
    super.initState();
    getList();
  }


  @override
  Widget build(BuildContext context) {
    return Scaffold();
}
}