Question

我需要帮助根据列值生成SQL结果以计算每日金额。

我有一个如下的SQL。

select guid, reccharge, dayCareDaysCharged, dayCareHoursPerDay, RATE from tableA.

如果reccharge = 0（每周），那么结果应该有7行，每行RATE为RATE / 7（每天数量）; 如果reccharge = 1（每月），那么结果应该有30行，每行的RATE为RATE / 30; 如果reccharge = 2（每年），那么结果应该有365行，每行的RATE为RATE / 365; 如果reccharge = 3（每小时）那么应该有一行计算一天;

我怎样才能做到这一点。请帮忙。

Answer 1

我不知道在单个查询中执行此操作，但您可以使用CURSOR执行此操作，如下所示：

declare @reccharge int
declare @count int
declare @i int
declare @strSQL nvarchar(max) = 'select 1, 1 where 1 <> 1'

declare CurTest cursor for select reccharge from test

open CurTest
fetch next from CurTest into @reccharge

while @@fetch_status = 0
begin
    set @i = 0; 

    select @count = case when @reccharge = 0 then 7 when @reccharge = 1 then 30 when @reccharge = 2 then 365 else 1 end

    while @i < @count 
    begin 
        set @strSQL = @strSQL + ' union all select reccharge, Rate/' + cast(@count as varchar(10)) + ' from test where reccharge = ' + cast(@reccharge as varchar(10))
        set @i = @i + 1; 
    end

fetch next from CurTest into @reccharge
end

close CurTest
deallocate CurTest

exec(@strSQL)

Answer 2

这个问题对我来说似乎有点奇怪，但如果我正确地遵循它，那么也许这就是

    CREATE TABLE [#temp1] (reccharge tinyint,rdays smallint)
    GO
    declare @rcount smallint
    set @rcount=0
    while @rcount<7
    begin
    set @rcount=@rcount+1
    insert #temp1 values (0,7)
    end
    set @rcount=0
    while @rcount<30
    begin
    set @rcount=@rcount+1
    insert #temp1 values (1,30)
    end
    set @rcount=0
    while @rcount<365
    begin
    set @rcount=@rcount+1
    insert #temp1 values (2,365)
    end
    insert #temp1 values (3,1)
    GO

    select t1.[guid], t1.reccharge, t1.dayCareDaysCharged, t1.dayCareHoursPerDay, t1.RATE/t2.rdays as RATE from tableA t1
    inner join #temp1 t2 on t1.reccharge=t2.reccharge
    order by t1.[guid]

需要根据列值重复结果行

2 个答案: