Question

我努力了，但我无法弄清楚出了什么问题。我想通过ajax发送一些参数，但每次出错都是如此。我的代码是：

    sendInsertValues : function(serviceCode, description, borrowerCoborrower, expiration, premiumValue,comissionValue,maxAge,companyCode) {         
        var callUrl = "http://localhost:9080/XA-UW0-PF/tmInsurance.do?method=add";
        var date = new Date();
        var time = date.getTime();

            $.ajax({            
             type        : "POST",
             url         : callUrl,
             data: "serviceCode=" + serviceCode+
                   "&description="+ description +
                   "&borrowerCoborrower="+ borrowerCoborrower +
                   "&expiration="+ expiration+
                   "&premiumValue="+ premiumValue+
                   "&comissionValue="+comissionValue+
                   "&maxAge="+maxAge+
                   "&companyCode="+companyCode+
                   "&time="+time,                
             success: function(data, textStatus, jqXHR)
                {
                       alert("Operation completed.");
                        window.close();
                 },
             error: function(jqXHR, textStatus, errorThrown) 
                 {
                        alert("Operation not completed.");

                 }          
});

}

我希望有人可以帮助我。谢谢！

Answer 1

数据应该是这样的

data:{ "serviceCode":serviceCode,
        "description":description,
        "borrowerCoborrower":borrowerCoborrower,
        "expiration":expiration,
        "premiumValue":premiumValue,
        "comissionValue":comissionValue,
        "maxAge":maxAge,
        "companyCode":companyCode,
         "time":time
      }

Answer 2

您需要将data作为JSON

传递

data:   {
        "serviceCode" :  serviceCode,
        "description":  description,  
        "borrowerCoborrower":  borrowerCoborrower, 
        "expiration":  expiration,
        "premiumValue":  premiumValue, 
        "comissionValue": comissionValue, 
        "maxAge": maxAge, 
        "companyCode": companyCode, 
        "time" : time
        }

Answer 3

你试过了吗？

data: { 'serviceCode': serviceCode, 'description' ... }

只需将参数作为JSON对象传递。

Answer 4

 sendInsertValues : function(serviceCode, description, borrowerCoborrower, expiration, premiumValue,comissionValue,maxAge,companyCode) {         
        var callUrl = "http://localhost:9080/XA-UW0-PF/tmInsurance.do?method=add", data = {
        "serviceCode" :  serviceCode,
        "description":  description,  
        "borrowerCoborrower":  borrowerCoborrower, 
        "expiration":  expiration,
        "premiumValue":  premiumValue, 
        "comissionValue": comissionValue, 
        "maxAge": maxAge, 
        "companyCode": companyCode, 
        "time" : time
        };

return $.post(callUrl, data).done(function(response) {
        alert("Operation completed.");
        window.close();
}).fail(function(error){alert("Operation not completed.");});
}

通过Ajax在Jquery中发送参数不起作用

4 个答案: