我创建了一个MVC项目,我希望从过滤器中将模型设置为视图。
但我不知道,我怎么能这样做。
模特:
public class TestModel
{
public int ID { get; set; }
public string Name { get; set; }
}
Contorller:
[CustomFilter(View = "../Test/Test")]//<===/Test/Test.cshtml
public ActionResult Test(TestModel testModel)//<===Model from Page
{
//the Model has Value!!
// if has some exception here
return View(model);//<=====/Test/Test.cshtml
}
过滤器(只是演示):
public override void OnActionExecuting(ActionExecutingContext filterContext){
ViewResult vr = new System.Web.Mvc.ViewResult()
{
ViewName = this.View,//<======/Test/Test.cshtml
ViewData = filterContext.Controller.ViewData
};
//How can I set Model here?!!
vr.Model = ???? //<========the Model is only get
filterContext.Result = vr;
}
编辑开始感谢@Richard Szalay @Zabavsky @James @spaceman
更改过滤器扩展到HandleErrorAttribute
ViewResult vr = new System.Web.Mvc.ViewResult()
{
ViewName = this.View,//<======/Test/Test.cshtml
ViewData = new ViewDataDictionary(filterContext.Controller.ViewData)
{
//I want get testModel from Action's paramater
//the filter extends HandleErrorAttribute
Model = new { ID = 3, Name = "test" }// set the model
}
};
修改结束
测试/ Test.chtml
@model TestModel
<h2>Test</h2>
@Model //<=====model is null
当我提出要求时
http://localhost/Test/Test?ID=3&Name=4
测试页无法获得模型。
答案 0 :(得分:20)
ViewResult vr = new System.Web.Mvc.ViewResult
{
ViewName = this.View, //<======/Test/Test.cshtml
ViewData = new ViewDataDictionary(filterContext.Controller.ViewData)
{
Model = // set the model
}
};
答案 1 :(得分:5)
来自asp.net mvc源,他们只是在视图数据中设置模型。 http://aspnetwebstack.codeplex.com/SourceControl/latest#src/System.Web.Mvc/Controller.cs
protected internal virtual ViewResult View(string viewName, string masterName, object model)
{
if (model != null)
{
ViewData.Model = model;
}
return new ViewResult
{
ViewName = viewName,
MasterName = masterName,
ViewData = ViewData,
TempData = TempData,
ViewEngineCollection = ViewEngineCollection
};
}
答案 2 :(得分:4)
您可以修改过滤器上下文,并设置View,Model,ViewData以及您想要的任何内容。你必须考虑一些事情:
// You can specify a model, and some extra info, like ViewBag:
ViewDataDictionary viewData = new ViewDataDictionary
{
Model = new MyViewModel
{
ModelProperty = ...,
OtherModelProperty = ...,
...
}
};
// You can take into account if it's a partial or not, to return a View
// or Partial View (casted to base, to set the remaining data):
ViewResultBase result = filterContext.IsChildAction
? new PartialViewResult()
: (ViewResultBase) (new ViewResult());
// Set the remaining data: Name of the View, (if in Shared folder) or
// Relative path to the view file with extension, like "~/Views/Misc/AView.cshtml"
result.ViewName = View;
result.ViewData = viewData; // as defined above
// Set this as the result
filterContext.Result = result;
通过这种方式,您的视图将根据需要接收模型。
答案 3 :(得分:3)
模型属性实际上只是一个ViewDataDictionary,你可以用你的实际模型初始化它的实例,即
vr.Model = new ViewDataDictionary(model);
答案 4 :(得分:0)
您可以从filtercontext中获取控制器,并在控制器上使用View方法,如下所示:
filterContext.Result = (filterContext.Controller as Controller).View(model);