Question

我想知道如何正确计算“平均步数等于”，因为步骤/ N在主方法中不起作用。如果我有100 / N而我的代码正确运行，但是我不知道如何总结TestWalk方法中的步骤然后返回到main。谢谢！

class Test { 

static int TestWalk() {

      int location = 5;
      int steps = 0;
      while (location != 0 && location !=10)
      {
         int direction = (int)(Math.random()*2);
         if (direction == 0)
         {
            location = location - 1;
         }
         if (direction == 1)
         {
            location = location + 1;
         }
         steps = steps + 1;
      }
      if (location == 0)
      {
         System.out.println ("Time for a walk!");
         System.out.println ("Took " + steps + " steps, and ");
         System.out.println ("Landed at HOME\n");
      }
      else
      {
         System.out.println ("Time for a walk!");
         System.out.println ("Took " + steps + " steps, and ");
         System.out.println ("Landed in Hospital\n");
      }
      return steps; }

      public static void main (String [] args) {
      final int N = 5;
      for(int i = 0; i<N; i++)
         TestWalk();
      System.out.println ("Average # of steps equals " + steps/N);
  }
}

Answer 1

您需要在main()中包含一个步骤变量，其中包含从TestWalk()返回的所有步骤的总和;方法

int steps = 0; // this is local to main and has nothing do with the steps in TestWalk() method
for(int i = 0; i<N; i++) {
    steps += TestWalk(); // steps will keep the sum of all the steps
}
System.out.println ("Average # of steps equals " + steps/N);

Answer 2

将你的方法主要归结为：

int steps = 0;
for(int i = 0; i<N; i++)
   steps += TestWalk();
System.out.println ("Average # of steps equals " + steps/N);

Answer 3

试试这个..

     public static void main (String [] args) {
      final int N = 5;
      int total = 0;
      for(int i = 0; i<N; i++)
        total+= TestWalk();
      System.out.println ("Average # of steps equals " + total/N);
}

从返回值计算平均值

3 个答案: