Question

我是PHP的初学者。我想从表到主页面显示我的mysql数据库内容作为数据库表中项目数的分页（有限制）。我的代码显示一个具有精确分页的格式，并在第一页中绘制项目（如：http://www.swaminarayantravel.com/category.php?sc=Trekking），但问题是，当我尝试从下面的分页转到第2页时，它会转到错误页面。我的代码是：

<?php

//get the function
include_once ('function.php');
include_once ('includes/connect.php');

    $page = (int) (!isset($_GET["page"]) ? 1 : $_GET["page"]);
    $limit = 4;
    $startpoint = ($page * $limit) - $limit;

    //to make pagination
  $sql = "category where category.category='$selcat'";
  ?>
<div class="records round">


  <ul class="homelist">
<?php

        //show records
 $query = mysql_query("SELECT * FROM {$sql} LIMIT {$startpoint} , {$limit}");
echo "<table>
<tr></tr>";

        while ($row = mysql_fetch_assoc($query)) {   ?>
<?php echo' <li > <img src="images/subcat/'.$row['file'] .'" height="100" width="100" alt="'.$row['subcategory'] .'"/> 
 <a class="title">'; 
$subcategory= $row["subcategory"];
                        echo "$subcategory"; 
echo'</a>
      <p align="justify">'; 
$detail= $row["subcat_detail"];
                        echo "$detail"; 
                        echo ' </p> '; ?> 
 <?php   }   ?> 
</table></div>
<?php   echo pagination($sql,$limit,$page);  ?>

和function.php页面包含以下代码：

<?php

功能分页（$ query，$ per_page = 10，$ page = 1，$ url ='？'）{
$ query =“SELECT COUNT（*）as num FROM {$ query}”; $ row = mysql_fetch_array（mysql_query（$ query））; $ total = $ row ['num']; $ adjacents =“2”;

    $page = ($page == 0 ? 1 : $page);  
    $start = ($page - 1) * $per_page;                               

    $prev = $page - 1;                          
    $next = $page + 1;
    $lastpage = ceil($total/$per_page);
    $lpm1 = $lastpage - 1;

    $pagination = "";
    if($lastpage > 1)
    {   
        $pagination .= "<ul class='pagination'>";
                $pagination .= "<li class='details'>Page $page of $lastpage</li>";
        if ($lastpage < 7 + ($adjacents * 2))
        {   
            for ($counter = 1; $counter <= $lastpage; $counter++)
            {
                if ($counter == $page)
                    $pagination.= "<li><a class='current'>$counter</a></li>";
                else
                    $pagination.= "<li><a href='{$url}page=$counter'>$counter</a></li>";                    
            }
        }
        elseif($lastpage > 5 + ($adjacents * 2))
        {
            if($page < 1 + ($adjacents * 2))        
            {
                for ($counter = 1; $counter < 4 + ($adjacents * 2); $counter++)
                {
                    if ($counter == $page)
                        $pagination.= "<li><a class='current'>$counter</a></li>";
                    else
                        $pagination.= "<li><a href='{$url}page=$counter'>$counter</a></li>";                    
                }
                $pagination.= "<li class='dot'>...</li>";
                $pagination.= "<li><a href='{$url}page=$lpm1'>$lpm1</a></li>";
                $pagination.= "<li><a href='{$url}page=$lastpage'>$lastpage</a></li>";      
            }
            elseif($lastpage - ($adjacents * 2) > $page && $page > ($adjacents * 2))
            {
                $pagination.= "<li><a href='{$url}page=1'>1</a></li>";
                $pagination.= "<li><a href='{$url}page=2'>2</a></li>";
                $pagination.= "<li class='dot'>...</li>";
                for ($counter = $page - $adjacents; $counter <= $page + $adjacents; $counter++)
                {
                    if ($counter == $page)
                        $pagination.= "<li><a class='current'>$counter</a></li>";
                    else
                        $pagination.= "<li><a href='{$url}page=$counter'>$counter</a></li>";                    
                }
                $pagination.= "<li class='dot'>..</li>";
                $pagination.= "<li><a href='{$url}page=$lpm1'>$lpm1</a></li>";
                $pagination.= "<li><a href='{$url}page=$lastpage'>$lastpage</a></li>";      
            }
            else
            {
                $pagination.= "<li><a href='{$url}page=1'>1</a></li>";
                $pagination.= "<li><a href='{$url}page=2'>2</a></li>";
                $pagination.= "<li class='dot'>..</li>";
                for ($counter = $lastpage - (2 + ($adjacents * 2)); $counter <= $lastpage; $counter++)
                {
                    if ($counter == $page)
                        $pagination.= "<li><a class='current'>$counter</a></li>";
                    else
                        $pagination.= "<li><a href='{$url}page=$counter'>$counter</a></li>";                    
                }
            }
        }

        if ($page < $counter - 1){ 
            $pagination.= "<li><a href='{$url}page=$next'>Next</a></li>";
            $pagination.= "<li><a href='{$url}page=$lastpage'>Last</a></li>";
        }else{
            $pagination.= "<li><a class='current'>Next</a></li>";
            $pagination.= "<li><a class='current'>Last</a></li>";
        }
        $pagination.= "</ul>\n";        
    }


    return $pagination;
}

＆GT;

Answer 1

您的代码很完美，但您忘记在请求网址中添加“sc = Trekking”。因此，在您的代码中，“$ selcat”可能变为空，并且sql查询不返回任何内容。

请试试这个： http://www.swaminarayantravel.com/category.php?sc=Trekking&page=2

也许你应该修改“分页”功能。

您的网站很精彩。我记得我在尼泊尔的旅行。

我的代码在PHP中的分页工作不正常，有什么建议吗？

1 个答案: