Question

我有一个装有安全问题和答案的SQL DB。我需要在html下拉列表中显示它们。我以为我可以使用while循环填充下拉字段，但我无法使其工作。

知道这有什么问题吗？

<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Untitled Document</title>
</head>

<body>

<?php

$conn = mysql_connect("localhost","root","")or die (mysql_error());

mysql_select_db("assignment_3", $conn);

$data = "select securityQuestion, securityAnswer from securityquestiontable";

$result = mysql_query($data, $conn) or die (mysql_error());

while ($row = mysql_fetch_assoc($result)) {
print "<select>";
print "<option value=""";
print "disabled="disabled" selected="selected">";
print "Please Select your Undergraduate School";
print "</option>";
print "<option value="1">";
print $row["securityQuestion"];
print "</option>";
print "<option value="2">";
print $row["securityAnswer"];
print "</option>";
print "</select>";
}

?>

</body>
</html>

Answer 1

您需要在外部打印语句。每次循环时，您都在创建一个新菜单。试试这个：

print "<select>"; while ($row = mysql_fetch_assoc($result)) { print "<option value="""; print "disabled="disabled" selected="selected">"; print "Please Select your Undergraduate School"; print "</option>"; print "<option value="1">"; print $row["securityQuestion"]; print "</option>"; print "<option value="2">"; print $row["securityAnswer"]; print "</option>"; } print "</select>";

Answer 2

尝试这样的事情：

echo '<select>';
while ($row = mysql_fetch_assoc($result)) {
    echo '<option value="" disabled="disabled" selected="selected">Please Select your Undergraduate School</option>';
    echo '<option value="1">'.$row["securityQuestion"].'</option>';
    echo '<option value="2">'.$row["securityAnswer"].'</option>';
}
echo '</select>';

或

print "<select>";
while ($row = mysql_fetch_assoc($result)) {
    print "<option value=""";
    print "disabled="disabled" selected="selected">";
    print "Please Select your Undergraduate School";
    print "</option>";
    print "<option value="1">";
    print $row["securityQuestion"];
    print "</option>";
    print "<option value="2">";
    print $row["securityAnswer"];
    print "</option>";
}
print "</select>";

我把选择标签放在循环外面。

Answer 3

您正在使用“无处不在，尝试此

来关闭您的打印件

print "<option value='1'>".$row['securityQuestion']."</option>";

而不是

print "<option value="1">$row["securityQuestion"]</option>";

同样在这里，试试这个

print "<option value='' disabled='disabled' selected='selected'> Please Select your Undergraduate School </option>";

而不是

print "<option value="" disabled="disabled" selected="selected"> Please Select your Undergraduate School </option>";

将你的选择放在你的循环之外。

Answer 4

你犯了一些小错误

请尝试此代码..

<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Untitled Document</title>
</head>

<body>

<?php

$conn = mysql_connect("localhost","root","")or die (mysql_error());

mysql_select_db("assignment_3", $conn);

$data = "select securityQuestion, securityAnswer from securityquestiontable";

$result = mysql_query($data, $conn) or die (mysql_error());
print "<select>";
while ($row = mysql_fetch_assoc($result)) {

print "<option value=""";
print "disabled="disabled" selected="selected">";
print "Please Select your Undergraduate School";
print "</option>";
print "<option value="1">";
print $row["securityQuestion"];
print "</option>";
print "<option value="2">";
print $row["securityAnswer"];
print "</option>";

}
print "</select>";
?>

</body>
</html>

在HTML下拉菜单中显示PHP变量

4 个答案: