该程序的目的是拍摄ppm图像并对其进行浮雕。 (可以找到整个项目的详细信息here)我正在帮助分配作业,似乎无法找到学生的错误。
我使用的原始图像如下所示:
结果应如下所示:
以下是整个程序(围绕问题行的评论):
# making an image embossed
import numpy
def clamp(color):
if color<0:
return 0
elif color>255:
return 255
else:
return color
def get_num(jen):
variable = ''
ch = gwen.read(1)
while ch.startswith('#'):
while ch!='\n':
ch=gwen.read(1)
while ch.isspace():
ch = gwen.read(1)
while ch.isspace():
ch = gwen.read(1)
while ch.isdigit():
variable = variable + ch
ch=gwen.read(1)
if ch.startswith('#'):
while ch!='\n':
ch=gwen.read(1)
return int(variable)
def emboss(x,y):
d=numpy.empty((h,w*3),numpy.uint8)
print "len x[0]=",len(x[0])
print "len y=", len(y)
print "len y[0]=", len(y[0])
for i in xrange(len(x)):
for j in xrange(0,len(x[0]),3):
for k in xrange(3): #r,g,b loop
#if the next line is used a correct (but not embosed) image results
#d[i][j+k] = x[i][j+k]
sum = 0
for l in xrange(0,3,1):
for m in xrange(0,3,1):
#the next line embosses but causes a triple image in the process
sum = sum + ((x[(i+(l-1))%h][((j+k)+((m-1)*3))%w]) * y[l][m])
#the line below adjusts an embossed images brightness
#if not embossing comment out this line
d[i][j+k]=clamp(sum+127)
return d
name=raw_input('Please enter input name: ')
output= raw_input('Please enter output name: ')
gwen=open(name,"rb")
ch=gwen.read(1)
if ch=='P':
print ('This is P')
else:
print('Error in Header')
ch=gwen.read(1)
if ch=='6':
print ('This is 6')
else:
print('Error in Header')
jen=''
w=get_num(jen)
w=int(w)
print w
h=get_num(jen)
h=int(h)
print h
value=get_num(jen)
value=int(value)
print value
joe=open(output,"wb")
joe.write('P6'+' '+str(w)+' '+str(h)+' '+str(value)+'\n')
a=numpy.fromfile(gwen,numpy.uint8, w*h*3,'')
c=numpy.reshape(a,(h,w*3))
d=numpy.array([[1,1,1],[0,0,0],[-1,-1,-1]])
new=emboss(c,d)
for i in xrange(h):
for j in xrange(0,w*3,3):
r_value = new[i][j]
r=int(clamp(r_value))
g_value = new[i][j+1]
g=int(clamp(g_value))
b_value = new[i][j+2]
b=int(clamp(b_value))
joe.write('%c%c%c'%(r,g,b))
gwen.close()
joe.close()
我觉得问题出在浮雕方法中,但似乎无法修复它。因此,我将其全部包含在过滤掉ppm标题注释的部分中。
就像现在一样,它会浮雕,但会这样做三重图像。 当压花线被移除时,三重图像会消失。
如果您想亲自尝试,我正在测试file
有什么建议我应该更改以修复错误?
答案 0 :(得分:4)
这是一个更清洁版的浮雕功能
# renamed
# x -> im (the input image numpy array)
# y -> kernel (the emboss kernel)
# i -> y (the y coordinate)
# j -> x (the x coordinate)
# d -> output (the output numpy array)
# k -> color (the number of the color channel 0-2)
# sum -> sum_ (sum is a built-in, so we shouldn't use that name)
def emboss(im,kernel):
output=numpy.empty((h,w*3),numpy.uint8)
print "len im[0]=",len(im[0])
print "len kernel=", len(kernel)
print "len kernel[0]=", len(kernel[0])
for y in xrange(len(im)):
for x in xrange(0,len(im[0]),3):
for color in xrange(3): #r,g,b loop
#if the next line is used a correct (but not embosed) image results
#output[y][x+color] = im[y][x+color]
sum_ = 0
for l in xrange(0,3,1):
for m in xrange(0,3,1):
#the next line embosses but causes a triple image in the process
sum_ += (im[(y+(l-1))%h][((x+color)+((m-1)*3))%w]) * kernel[l][m]
#the line below adjusts an embossed images brightness
#if not embossing comment out this line
output[y][x+color]=clamp(sum_+127)
return output
该错误似乎就在这一行
sum_ += (im[(y+(l-1))%h][((x+color)+((m-1)*3))%w]) * kernel[l][m]
x-coord mod
由w
编辑的位置(图像宽度,以像素为单位)。 x-coord
在0-1920之间变化(由于3通道颜色),而图像宽度仅为640px。 mod
(w * 3)应该纠正问题。
以下是原始代码的修复:
sum = sum + ((x[(i+(l-1))%h][((j+k)+((m-1)*3))%(w*3)]) * y[l][m])
答案 1 :(得分:3)
代码需要很多改进,但对于错误:
sum = sum + ((x[(i+(l-1))%h][((j+k)+((m-1)*3))%(w*3)]) * y[l][m]) # %(w*3)