Question

我在drawable文件夹中有这些图像：

image_1.png
image_2.png
image_3.png
...
image_n.png

我有一个像这样的id属性的PlayerDTO：

public class PlayerDTO implements Serializable {

    private static final long serialVersionUID = 1L;
    private int id;

    //... getters and setters

}

我需要在播放器ID和相应的图像之间建立匹配，以便在ImageView中设置它。 e.g：

player id = 1. It's image is image_1.png
player id = 2. It's image is image_2.png
...
player id = n. It's image is image_n.png

这是相同的，但这不是动态的：

ImageView imageView = (ImageView) findViewById(R.id.image);
imageView.setImageResource(R.drawable.image_1);

如何以编程方式动态完成此操作？

Answer 1

如果您的意思是尝试以编程方式获取资源名称，那么就这样：

int[] drawableId = new int[totalNumberOfImages];
String drawableName;
for (int n = 1; n < totalNumberOfImages; n++) {
    drawableName = "image_" + n;
    drawableId[n] = getResources().getIdentifier(drawableName, "drawable", getPackageName());
}

这将为您提供一系列可绘制的ID。

要获得直接关联，您可以使用SparseIntArray，例如：

int drawableId;
String drawableName;
SparseIntArray playerImages = new SparseIntArray(totalNumberOfPlayers);
for (int n = 1; n < totalNumberOfPlayers; n++) {
    drawableName = "image_" + n;
    drawableId = getResources().getIdentifier(drawableName, "drawable", getPackageName());
    playerImages.put(n, drawableId);
}

以编程方式显示位于可绘制文件夹中的图像

1 个答案: