Question

我有一个用户可以登录的页面。一个php脚本检查登录值。问题是，当我在表单中输入我的详细信息时，我会被重定向到.php页面，但我得到一个空白屏幕。当我刷新该屏幕时，它会显示“Unsuccesfull”，因为我的电子邮件和密码值因为刷新而不再设置。

为什么在按“登录”后会出现空白页？

<!DOCTYPE html>
<html>
    <head>
        <title>Grippee - Login</title>
                <link rel="stylesheet" href="style2.css" />
        <meta content="text/html;charset=utf-8" http-equiv="Content-Type">
        <meta content="utf-8" http-equiv="encoding">
        <meta name="viewport" content="width=device-width, initial-scale=1">
        <link rel="stylesheet" href="http://code.jquery.com/mobile/1.3.2/jquery.mobile-1.3.2.min.css" />
        <link rel="stylesheet" href="themes/customtheme.css" />
        <script type="text/javascript" src="http://code.jquery.com/jquery-1.9.1.min.js"></script>
        <script src="http://code.jquery.com/mobile/1.3.2/jquery.mobile-1.3.2.min.js"></script>
    </head>
    <body>
        <div data-role="page">
            <div data-role="header">
                <a class="ui-btn-left" href="index.html" data-icon="back">Terug</a>
                <h1><span>Login</span></h1>
                <a class="ui-btn-right" href="#" data-icon="info">i & &euro;</a>
            </div>
            <div data-role="content" data-position="relative">
                <div class="loginform">
                    <form id="loginForm" action="login.php" method="POST">
                        <span>Email adres:</span>
                        <input type="text" name="email" id="email"></input>
                        <span>Wachtwoord:</span>
                        <input type="password" name="password" id="password"></input>
                        <input type="submit" value="Login" />
                    </form>
                </div>
            </div>
            <div data-role="footer" data-position="fixed"></div>
        </div>
    </body>
</html>

PHP：

<?php
    $email = "";
    $password = "";
    if (isset($_POST["email"]))
    {
        $email = $_POST["email"];
        echo ($email);
    } 
    else {
        echo("Something is wrong");
    }
    if (isset($_POST["password"]))
    {
        $password = $_POST["password"];
        echo($password);
    }

    $mysqli = new mysqli('localhost', 'qq', 'qq', 'qq', 3306);
    if ($mysqli->connect_errno) {
        echo "Failed to connect to MySQL: (" . $mysqli->connect_errno . ") " . $mysqli->connect_error;
    }

    $result = $mysqli->query("SELECT id FROM Consument WHERE email = '$email' AND wachtwoord = '$password'");
    $rows = $result->num_rows;

    if ($rows == 1)
        echo ("Logged in!");
    else
        echo ("Unsuccesfull!"); 
?>

Answer 1

查询不正确。

使用它：

$result = $mysqli->query("SELECT * FROM Customer WHERE email = " . $email . " AND wachtwoord = " . $password);

Answer 2

我修改了一下你的PHP。尝试一下吧。即使这样也不是最好的方法，但是......

<?php
   //enable all kind of errors to can debug properly   
   ini_set('display_errors',1);
   ini_set('display_startup_errors',1);
   error_reporting(-1);

    $email = "";
    $password = "";

    if ( isset($_POST["email"]) && isset($_POST["password"]))
    {
        $email = $_POST["email"];
        $password = $_POST["password"];
        echo ($email);
        echo($password);

    $mysqli = new mysqli('localhost', 'qq', 'qq', 'qq', 3306);
    if ($mysqli->connect_errno) {
        echo "Failed to connect to MySQL: (" . $mysqli->connect_errno . ") " . $mysqli->connect_error;
    }

    $result = $mysqli->query("SELECT * FROM Customer WHERE email = '".$email."' and wachtwoord = '".$password."'");
    $rows = mysql_num_rows($result);

    if ($rows == 1)
        echo ("Logged in!");
    else
        echo ("Unsuccesfull!"); 

    } 
    else {
        echo("Something is wrong");
    }

?>

php表单提交无法正常工作

2 个答案: