Question

我想把这个名字变成欢迎信息，比如“欢迎，！”是的，网上有很多文章可以为您提供编码，而不是在我的代码出现问题时。

无论如何，我的登录页面使用电子邮件和密码：

 <?php
 session_start();

 if (isset($_POST['login']))
 {
       $email = mysql_real_escape_string(isset($_POST['email']) ? stripslashes($_POST['email']) : false);
   $password = mysql_real_escape_string(isset($_POST['password']) ? stripslashes($_POST['password']) : false);

   if ($email&&$password)
   {
    require "connect.php";
    $query = mysql_query("SELECT * FROM register WHERE email LIKE '$email'");       
    $numrows = mysql_num_rows($query);

    if (1 == $numrows)
    {   
        $rows = mysql_fetch_assoc($query)

        if ($email==$rows['email'] && $password==$rows['password'])
        {
            $_SESSION['email']=$rows['email'];
            $_SESSION['name']=$rows['name'];
            header("Location: profile.php");
        }
        else 
        {
            echo ('<script type="text/javascript">alert("Incorrect Password");</script>');
            header("Location: index.php");
        }
    }
    else 
    {
        echo ('<script type="text/javascript">alert("The Email Does Not Exist In Database");</script>');
        header("Location: index.php");
    }
   }
   else 
   {
    echo ('<script type="text/javascript">alert("Please Enter An Email and/or Password");</script>');
    header("Location: index.php");
   }
}

  exit();
  ?>
<form name="flogin" action="index.php" method="post">
<table width="350px">
    <tr>
        <td ><b>Email :</b></td>
        <td><input  type="text" name="email"></td>
    </tr>
    <tr>
        <td><b>Password :</b></td>
        <td><input  type="password" name="password"></td>
    </tr>
</table>
<div><input type="submit" class="login" value="Login" name="login"></div> 
</form>

但我收到此错误Parse error: syntax error, unexpected 'if' (T_IF) in C:\xampp\htdocs\CashFlow\index.php on line 19

和我的个人资料.php

    <?php
    session_start();

    require "connect.php";
    if($_SESSION['name'])
    {
$name =  $_SESSION['name'];
$query =  mysql_query("SELECT name FROM register WHERE name ='$name'");
$numrows = mysql_num_rows($query);

if(1 == $numrows)
{
    while ($rows = mysql_fetch_assoc($query))
    {
        echo "Welcome, ".$rows['name']."!"; 
    }
}
    }
    ?>

但我得到了这个：

Notice: Undefined index: name in C:\xampp\htdocs\CashFlow\profile.php on line 5

我做错了什么？

Answer 1

在线：

 if ($email && $password) {
    require "connect.php";

你永远不会关闭那个括号。

Answer 2

你缺少花括号}。

<?php
if (isset($_POST['login'])) { // you never closed this if statement
.....
......
}
} // Add these in your code.
exit();
?>

使用电子邮件登录，但欢迎消息是名称

2 个答案: