我有一个cs课程的项目将于下周末到期,我已经完成了它,但我遇到了一些问题,我一直在尝试一切,但无法让它发挥作用。我们的项目包括从输入文件中获取3个月的3个客户信息和每月公用事业费用,将所有这些存储在数组中,然后计算小计,税,折扣和总付款,然后将其存储到数组中,然后输出1个季度收据为每个客户。我们必须使用函数来做到这一点。我的主要问题是,它只输出第一个客户收据,我已经双重检查了我的for循环,对我来说它看起来应该有效。
非常感谢
继承输出文件
Austin City Office, Texas
RECEIPT #59, September28, 2013, 09:00PM
客户ID:127654 姓名:杰克琼斯 地址:2059 Joe Lane,Austin TX,78646 电话号码:512-520-5862
电费:6美元 水费:24美元 燃气费:12美元
小计:42美元 折扣金额:0.84美元(由于您的小计小于100美元,折扣2%)
折扣后小计:41.16美元(加2%折扣)
销售税金额:2.4696美元(自折扣后的小计金额低于100美元以来的6%税)
支付的总金额:$ 43.6296(增加6%的销售税)
............................................... .................................................. .... 退款政策:如果在付款之日起30天内报告错误,则为100%。只有75%的退款 30天后。 感谢您及时付款。
继承我的输入文件
Austin City Office, Texas
RECEIPT #59, September28, 2013, 09:00PM
Refund Policy: 100% if an error is reported within 30 days from the date of payment. Only 75% refund
after 30 days.
Thank you for prompt payment.
127654
Jack Jones
2059 Joe Lane, Austin TX, 78646
512-520-5862
2
8
4
2
8
4
2
8
4
Austin City Office, Texas
RECEIPT #59, September28, 2013, 09:00PM
Refund Policy: 100% if an error is reported within 30 days from the date of payment. Only 75% refund
after 30 days.
Thank you for prompt payment.
124325
Jack Williams
2788 Eagle Drive, Austin TX, 78646
512-623-7676
2
8
20
2
8
20
2
8
20
Austin City Office, Texas
RECEIPT #59, September28, 2013, 09:00PM
Refund Policy: 100% if an error is reported within 30 days from the date of payment. Only 75% refund
after 30 days.
Thank you for prompt payment.
125672
John Jones
3422 Hawk Drive, Austin TX, 78646
512-522-4564
2
8
40
2
8
40
2
8
40
和我的代码
#include<iostream>
#include<iomanip>
#include<string>
#include<string>
#include<fstream>
using namespace std;
//define varibles
int ncustomer1;
double discount, tax;
string dc, dsc, tc, dtpc;
//validation constant
const int MIN_N = 1, MAX_N = 3, MAX_TITLE=200, MAX_CINFO=200;
const float MIN_CHARGE=1.00, MAX_CHARGE= 1000.00;
// Array constant
const int MAX_NUMCUST=3, MAX_NUMMONTH=3, MAX_NUMCHARGE=3, MAX_NUMHEAD=6, MAX_NUMINFO=9, MAX_NUMTOTAL=8;
//customer info array
string NonNum[MAX_NUMCUST][MAX_NUMINFO];
//charges array
double Num[MAX_NUMCUST][MAX_NUMMONTH][MAX_NUMCHARGE] = {0};
//calculated array
double custTotals[MAX_NUMCUST][MAX_NUMTOTAL] = {0};
//functions
void input(string NonNum[MAX_NUMCUST][MAX_NUMINFO], double Num[MAX_NUMCUST][MAX_NUMMONTH][MAX_NUMCHARGE], int& count);
double subtotal(double custTotals[MAX_NUMCUST][MAX_NUMTOTAL], int&count);
double discount1(double custTotals[MAX_NUMCUST][MAX_NUMTOTAL], int&count);
double tax1(double custTotals[MAX_NUMCUST][MAX_NUMTOTAL], int&count);
void receipts(double custTotals[MAX_NUMCUST][MAX_NUMTOTAL], string NonNum[MAX_NUMCUST][MAX_NUMINFO], int&count);
int main()
{
//Ask number of customers from user
cout<< "Enter a number for amount of customers you would like to make a receipt for number should be between 1 and 3."<<endl;
cin >> ncustomer1;
//validate users entry
while(ncustomer1 > MAX_N || ncustomer1 < MIN_N )
{
cout << "Error: the number of customers must be between "<< MIN_N << " and "<< MAX_N <<endl;
cout<< "Re-Enter the number of customers"<<endl;
cin>> ncustomer1;
}
//output to screen when users entry is correct
cout<< "Ok, individual receipt(s) will be added to the output file for "<< ncustomer1<< " customer(s)."<<endl;
//customer for loop
for (int count = 0; count < ncustomer1; ++count)
{
input(NonNum, Num, count);
subtotal(custTotals, count);
discount1(custTotals, count);
tax1(custTotals, count);
receipts(custTotals, NonNum, count);
}
return 0;
}
//functions
void input(string NonNum[MAX_NUMCUST][MAX_NUMINFO], double Num[MAX_NUMCUST][MAX_NUMMONTH][MAX_NUMCHARGE], int& count)
{
//objects to help read input file
ifstream inputFile;
//open the input file
inputFile.open("Project5_a02418790_Input.txt");
//validation of input file
if(!inputFile)
{
cout<<"error opening input file.";
}
// For loop for non numeric data id, number...
for(int head = 0; head < 9; ++head)
{
//Get customer data as strings from input
getline(inputFile,NonNum[count][head]);
/* Validate inputed customer data
if(NonNum[count][head].length()>MAX_CINFO)
{
cout<<"customer "<<count<<"(customers are from 0-X, so customer 1=0) heading "<<head<<" String is too long"<<endl;
continue;
}
*/
}//end non numeric data for loop
//number of months For loop
for(int mnth = 0; mnth < 3; ++mnth)
{
//number of charges For loop
for(int charge = 0; charge < 3; ++charge)
{
//input charges
inputFile >> Num[count][mnth][charge];
//Running totals of the 3 charges
custTotals[count][charge] += Num[count][mnth][charge];
}//end of number of charges for loop
}//end of number of months foor loop
}
double subtotal(double custTotals[MAX_NUMCUST][MAX_NUMTOTAL], int&count)
{
// calculate the subtotal
//subtotal = Elec total + Water Total + Gas Total
custTotals[count][3]=custTotals[count][0]+custTotals[count][1]+custTotals[count][2];
}
double discount1(double custTotals[MAX_NUMCUST][MAX_NUMTOTAL], int&count)
{
//figure out the discount based on the subtotal
//if(subtotal=,<,> a number)
// discount%= x, comment= x;
if(custTotals[count][3]<100)
discount= .02, dc = "(2% discount since your subtotal is less than $100)", dsc="(With 2% discount added)";
if(custTotals[count][3]>=100&&custTotals[count][3]<250)
discount= .03, dc = "(3% discount since your subtotal is greater or equal to $100)", dsc="(With 3% discount added)";
if(custTotals[count][3]>=250&&custTotals[count][3]<500)
discount=.04, dc = "(4% discount since your subtotal is greater or equal to $250)", dsc="(With 4% discount added)";
if(custTotals[count][3]>=500)
discount=.05, dc = "(5% discount since subtotal is greater or equal to $500)", dsc="(With 5% discount added)";
//calculate the amount of discount
//discount amount = subtotal * discount %
custTotals[count][4] = custTotals[count][3]*discount;
//calculate the subtotal after the discount
//subtotal after dis= subtotal - discount
custTotals[count][5]=custTotals[count][3]-custTotals[count][4];
}
double tax1(double custTotals[MAX_NUMCUST][MAX_NUMTOTAL], int&count)
{
//figure out how sales tax percent and what captions
//if(subtotal after dis =,<,> a num)
// tax percent= x, comment= x;
if(custTotals[count][5]< 100 )
tax= .06, tc="(6% Tax since your subtotal after the discount is less than $100)", dtpc= "(With 6% Sales Tax added)";
if( custTotals[count][5] >=100&& custTotals[count][5] <250)
tax= .07, tc="(7% Tax since your subtotal after the discount is greater or equal to $100)", dtpc= "(With 7% Sales Tax added)";
if( custTotals[count][5] >=250&& custTotals[count][5] <500)
tax=.08, tc="(8% Tax since your subtotal after the discount is greater or equal to $250)", dtpc= "(With 8% Sales Tax added)";
if( custTotals[count][5] >=500)
tax=.09, tc="(9% Tax since your subtotal after the discount is greater or equal to $500)", dtpc= "(With 9% Sales Tax added)";
//calculate the sales tax amount
//amount of tax = subtotal after dis * tax percent
custTotals[count][6]= custTotals[count][5]*tax;
//calculate total amount paid
//total paid = subtotal after dis + amount of tax
custTotals[count][7]= custTotals[count][5] + custTotals[count][6];
}
void receipts(double custTotals[MAX_NUMCUST][MAX_NUMTOTAL], string NonNum[MAX_NUMCUST][MAX_NUMINFO], int&count)
{
//objects to help read output file
ofstream outputFile;
//open the output file
outputFile.open("Project5_a02418790_Output.txt");
//validation of output file
if(!outputFile)
{
cout<<"error opening output file.";
}
//OUTPUT ALL NEEDED INFO (STILL INSIDE CUSTOMER FOR LOOP)
//OUTPUT HEADER
outputFile<<setw(58)<<NonNum[count][0]<<endl<<setw(70)<<NonNum[count][1]<<endl;
//OUTPUT CUSTOMER INFO FOR LOOP
for(int z = 5; z < 9; ++z)
{
while(z == 5 )//Customer ID
{
outputFile<<endl<<"Customer ID: "<<NonNum[count][z]<< endl;
break;
}
while(z == 6 )//Name
{
outputFile<<"Name: "<<NonNum[count][z]<< endl;
break;
}
while(z == 7 )//Address
{
outputFile<<"Address: "<<NonNum[count][z]<< endl;
break;
}
while(z == 8 )//Phone Number
{
outputFile<<"Phone Number: "<<NonNum[count][z]<< endl;
break;
}
}//END OF OUTPUT CUSTOMER INFO FOR LOOP
//OUTPUT CHARGES AND TOTALS FOR LOOP
for(int y = 0; y < 8; ++y)
{
while(y == 0 )//Electricity Charges
{
outputFile<<endl<<"Electricity Charges: $"<<custTotals[count][y] << endl;
break;
}
while(y == 1 )//Water Charges
{
outputFile<<"Water Charges: $"<<custTotals[count][y] << endl;
break;
}
while(y == 2 )//Gas Charges
{
outputFile<<"Gas Charges: $"<<custTotals[count][y] << endl<<endl;
break;
}
while(y == 3 )//Subtotal
{
outputFile<<"Subtotal: $"<<custTotals[count][y] << endl;
break;
}
while(y == 4)//Discount Amount
{
outputFile<<"Discount Amount: $"<<custTotals[count][y]<<" "<<dc<< endl<<endl;
break;
}
while(y == 5 )//Subtotal After the Discount
{
outputFile<<"Subtotal After the Discount: $"<<custTotals[count][y]<<" "<<dsc<< endl<<endl;
break;
}
while(y == 6 )//Sales Tax Amount
{
outputFile<<"Sales Tax Amount: $"<<custTotals[count][y]<<" "<<tc<< endl<<endl;
break;
}
while(y == 7 )//Total Amount Paid
{
outputFile<<"Total Amount Paid: $"<<custTotals[count][y]<<" "<<dtpc<< endl<<endl;
break;
}
}//END OF OUTPUT CHARGES AND TOTALS FOR LOOP
//OUTPUT FOOTER BREAK
outputFile<<"....................................................................................................."<<endl;
//OUTPUT REFUND FOR LOOP
for(int w = 2; w < 4; ++w)
{
outputFile<< NonNum[count][w]<<endl;
}
//OUTPUT THANKYOU
outputFile<<setw(58)<<NonNum[count][4]<<endl;
//OUTPUT NEW LINE AND DIVIDER FOR NEW CUSTOMER
outputFile<<endl<<"_____________________________________________________________________________________________________"<<endl<<endl;
}
答案 0 :(得分:0)
你确定它每次写第一个吗?在我看来,它会编写最后一个,因为你在每次调用收据时都会将文件写入,而不是附加到它。
获得一组输出IMHO的关键原因是这一行
outputFile.open("Project5_a02418790_Output.txt");
因为每次调用收据都会调用它,所以每次都会覆盖文件,只得到一组输出。
还有很多其他的东西都是非常糟糕的编码习惯。
问题1:使用数组,您应该使用Structures /或类: 例如:您将客户信息保存在字符串数组的数组中。
std::string NonNum[MAX_NUMCUST][MAX_NUMINFO]
然后NonNum [1] [5]是客户1的customerID的ID。您应该构建一个结构,它将使您的代码更容易理解。正确命名NonNum告诉我们它包含我们从代码中看到的字符串,它没有告诉我们存储什么类型的信息的重要信息(客户ID /地址等)。
另见:
for(int z = 5; z < 9; ++z) {
while(z == 5 )//Customer ID {
outputFile<<endl<<"Customer ID: "<<NonNum[count][z]<< endl;
break;
while(z==6) { ...
}
内心的意义何在?你为什么需要循环?不会写得容易得多:
OUTPUTFILE&LT;&LT; &#34;客户ID:&#34; &LT;&LT; CustomerInfo [i] .CustomerID&lt;&lt; ENDL;
问题2:函数之间的依赖关系
小计填写custTotals[i][3]
并取决于custTotals[i][0]
,custTotals[i][1]
&amp; custTotals[i][2]
discount1根据之前的那些填充custTotals [i] [4]。再次,您使用的是一个应该使用结构的数组。但如果功能的输入和输出清晰易懂,它也会让您的生活更轻松。
目前,函数顺序的任何变化都会使逻辑变得混乱,但是从代码中看不到它。
如果您有一个单独的subTotals数组,您将传递给subTotals,因此它会写入然后传递给Discount1,以便从所有内容中读取更清晰。
问题3:你传递了一个int&amp;计算所有这些功能,但您不打算更改它。我预计错误是你写的内部函数之一,并没有意识到它。如果将非常量引用传递给对象,则表示这是函数的输出而不是输入。