mysql从两个单独的查询中创建选择结果

Question

我正在尝试创建一个sql查询，创建一个联赛表，其中包含团队名称，游戏，总得分和平均每场得分。

对比赛的查询是： 选择team_name， COUNT（*）AS games_played 来自fixtures GROUP BY team_name;

得分总分的查询是： 选择teams。team_name， COUNT（*）AS total_points_gained 来自scores，players，teams 在scores。player_id = players。player_id 和players。team_name = teams。team_name GROUP BY teams。team_name

如何组合这两个查询以获取一个结果中的所有数据？

Answer 1

这应该有效：

SELECT teams.team_name, COUNT(*) AS total_points_gained,
(SELECT COUNT(*) FROM fixtures WHERE fixtures.team_name = teams.team_name) AS games_played 
FROM scores,players,teams 
WHERE scores.player_id=players.player_id 
AND players.team_name = teams.team_name 
GROUP BY teams.team_name

Answer 2

您应该阅读有关JOIN的信息。通过JOIN，您可以将这两个查询（例如按团队名称）合并为一个结果。