Question

我正在使用Java中的套接字编写代理，现在我遇到了一个奇怪的问题（我认为问题是标题）... 当我尝试将URL发送回客户端（在本例中为webbrowser）时，如果我连接到www.google.com，我会收到此错误：

这是一个错误。您的客户发出了格式错误或非法的请求。这就是我们所知道的。

但奇怪的是，还有其他网络工作正常并且没有出现任何错误......

对此有任何帮助将不胜感激......

感谢。

这是代码：

import java.io.*;
import java.net.*;
import java.nio.charset.Charset;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;

public class Server {


public void startServer() {
    final ExecutorService clientProcessingPool = Executors.newFixedThreadPool(10);

    Runnable serverTask = new Runnable() {
        @Override
        public void run() {
            try {
                @SuppressWarnings("resource")
                ServerSocket serverSocket = new ServerSocket(80);
                while (true) {
                    Socket clientSocket = serverSocket.accept();
                    clientProcessingPool.submit(new ClientTask(clientSocket));
                }
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
    };
    Thread serverThread = new Thread(serverTask);
    serverThread.start();

}

private class ClientTask implements Runnable {
    private final Socket clientSocket;

    private ClientTask(Socket clientSocket) {
        this.clientSocket = clientSocket;
    }

    @Override
    public void run() {

        try {

            String url = null;
            BufferedReader in = new BufferedReader(new InputStreamReader(clientSocket.getInputStream(), "ISO-8859-1"));
            BufferedWriter out = new BufferedWriter(new OutputStreamWriter(clientSocket.getOutputStream()));




            StringBuilder builder = new StringBuilder();
            for (String buffer; (buffer = in.readLine()) != null;) {
            if (buffer.isEmpty()) break;
            builder.append(buffer.replaceAll("keep-alive", "close")+"\r\n");
            if(buffer.contains("Host"))
                {
                //parse the host
                url = buffer.replaceAll("Host: ", "");
                }
            //System.out.println(builder);
            }

   if (url.contains("elotrolado.net")){         

            out.write("HTTP/1.1 200 OK\r\n");
            out.write("Date: Fri, 31 Dec 1999 23:59:59 GMT\r\n");
            out.write("Server: Apache/0.8.4\r\n");
            out.write("Content-Type: text/html\r\n");
            out.write("Expires: Sat, 01 Jan 2000 00:59:59 GMT\r\n");
            out.write("Last-modified: Fri, 09 Aug 1996 14:21:40 GMT\r\n");
            out.write("\r\n");
            out.write("<TITLE>DENEGADO</TITLE>");
            out.write("<P>Acceso a "+url+" denegado</P>");
            out.close();
            in.close();
            clientSocket.close();         

   }
   else
   {

            String IP = InetAddress.getByName(url).getHostAddress().toString();                

            //new socket to send the information over

            Socket ss = new Socket(url, 80);
            //printwriter to send text over the output stream
            PrintWriter pw = new PrintWriter(ss.getOutputStream()); 

            //send the request from the client
            String req = builder.toString();
            System.out.println(req);
            String reqq=URLEncoder.encode(req, "UTF-8");
            pw.println(reqq);
            pw.flush();

            //create inputstream to receive the web page from the host
            BufferedInputStream inn = new BufferedInputStream(ss.getInputStream());

            //create outputstream to send the web page to the client
            BufferedOutputStream outt = new BufferedOutputStream(clientSocket.getOutputStream());

            byte[] bytebuffer = new byte[1024];
            int bytesread;

            //send the response back to the client
            while((bytesread = inn.read(bytebuffer)) != -1) {
            outt.write(bytebuffer,0, bytesread);
            outt.flush();
            }

            ss.close();
            pw.close();
            outt.close();
            inn.close();
            out.close();
            in.close();
            clientSocket.close();
            }

        } catch (IOException e) {
            e.printStackTrace();
        }catch(RuntimeException e){
            e.printStackTrace();
        }
    }
}

带有标头的Java套接字问题

0 个答案: