Question

我正在尝试用null或其他一些字符替换\“，并尝试JSON解析，但它不会发生在al。下面是我的代码。

var s = '{"total":2,"data":[{"assignExist":"Online","status":"Started Work","state":"Ready for Download","assignInfoletId":"100003","loadAssignId":"false","assignAdditionalInfo":[{}],"assignName":"BC Simple Form","assignId":"100003","assignProcessId":"3"},{"assignExist":"Online","status":"Started Work","state":"Ready for Download","assignInfoletId":"100003","loadAssignId":"false","assignAdditionalInfo":[{"Name":"Rishant","City":"Bangalore","Desc":"Platform-Dev","AUDIT_COMPANIES":"[{\"AUDIT_COMPANY\":\"Golder\",\"AUDITORS\":[{\"TPA_AUDITOR\":\"Swadhin Ray\",\"IS_LEAD\":\"0\",\"ASSIGNMENTS\":\"Assigmens, Sdsfds,sdfdsfd\"},{\"TPA_AUDITOR\":\"Praveen Kayetha\",\"IS_LEAD\":\"1\",\"ASSIGNMENTS\":\"Assigmens, Sdsfds,sdfdsfd\"}]}]"}],"assignName":"BC Simple Form","assignId":"100001","assignProcessId":"2"}]}';


s= s.replace(/\\"/g, "DOUBLEQ");

console.log(s);
var data = JSON.parse(s);
console.log(data);

我找到的解决方案是

var dataResponse = JSON.parse(s);

      var dataLen = dataResponse.data.length;

      for(var i=0;i<dataLen;i++){
        var audit_co = dataResponse.data[i].assignAdditionalInfo[0].AUDIT_COMPANIES;
        if(typeof audit_co!= 'undefined')
          dataResponse.data[i].assignAdditionalInfo[0].AUDIT_COMPANIES = JSON.parse(audit_co.replace(/\\"/g,'"'));
      }

Answer 1

我不认为这是非法的JSON - 它看起来像JSON中的JSON，这是有效的。尝试解析它而不改变它。

Answer 2

您无需将其解析为无效的JSON：
您可以直接访问值：

<script>
    var s = {"total":2,"data":[{"assignExist":"Online","status":"Started Work","state":"Ready for Download","assignInfoletId":"100003","loadAssignId":"false","assignAdditionalInfo":[{}],"assignName":"BC Simple Form","assignId":"100003","assignProcessId":"3"},{"assignExist":"Online","status":"Started Work","state":"Ready for Download","assignInfoletId":"100003","loadAssignId":"false","assignAdditionalInfo":[{"Name":"Rishant","City":"Bangalore","Desc":"Platform-Dev","AUDIT_COMPANIES":"[{\"AUDIT_COMPANY\":\"Golder\",\"AUDITORS\":[{\"TPA_AUDITOR\":\"Swadhin Ray\",\"IS_LEAD\":\"0\",\"ASSIGNMENTS\":\"Assigmens, Sdsfds,sdfdsfd\"},{\"TPA_AUDITOR\":\"Praveen Kayetha\",\"IS_LEAD\":\"1\",\"ASSIGNMENTS\":\"Assigmens, Sdsfds,sdfdsfd\"}]}]"}],"assignName":"BC Simple Form","assignId":"100001","assignProcessId":"2"}]};
    console.log(s.data);
</script>

Answer 3

目前你有这个：

var s = '{"plainValue": 42, "nestedJSON": "{\"nested\": \"json\"}"}';

这是无效的，因为它转换为以下内存中的字符串：

{"plainValue": 42, "nestedJSON": "{"nested": "json"}"}
                                   ^      ^  ^    ^     invalid double quotes

解决方案很简单：不要使用嵌套的JSON。 没有任何理由将JSON字符串嵌套到JSON字符串中。这是你应该拥有的。

var s = '{"plainValue": 42, "nestedObject": {"nested": "object"}}';

语法上有效但愚蠢的是

var s = '{"plainValue": 42, "nestedJSON": "{\\"nested\\": \\"json\\"}"}';

在源头修复问题。生成JSON字符串的函数已损坏。

Answer 4

当你创建's'字符串时，\“已经被转义，所以\ char消失。这就是为什么你不能用某些东西替换\”，因为它不存在。

Answer 5

以下方法应该起作用：

var s = JSON.stringify({"total":2,"data":[{"assignExist":"Online","status":"Started Work","state":"Ready for Download","assignInfoletId":"100003","loadAssignId":"false","assignAdditionalInfo":[{}],"assignName":"BC Simple Form","assignId":"100003","assignProcessId":"3"},{"assignExist":"Online","status":"Started Work","state":"Ready for Download","assignInfoletId":"100003","loadAssignId":"false","assignAdditionalInfo":[{"Name":"Rishant","City":"Bangalore","Desc":"Platform-Dev","AUDIT_COMPANIES":"[{\"AUDIT_COMPANY\":\"Golder\",\"AUDITORS\":[{\"TPA_AUDITOR\":\"Swadhin Ray\",\"IS_LEAD\":\"0\",\"ASSIGNMENTS\":\"Assigmens, Sdsfds,sdfdsfd\"},{\"TPA_AUDITOR\":\"Praveen Kayetha\",\"IS_LEAD\":\"1\",\"ASSIGNMENTS\":\"Assigmens, Sdsfds,sdfdsfd\"}]}]"}],"assignName":"BC Simple Form","assignId":"100001","assignProcessId":"2"}]});

var data = JSON.parse(s);

Javascript：替换反斜杠和双引号与其他一些char

5 个答案: