<title>Javascript</title>
<script>
function buttonreport(id,name,address){
var userid ="Id:"+id;
var username="Name :"+name+"\n";
var useraddress ="Address:"+address+"\n";
alert(userid+username+useraddress);
}
</script>
</head>
<body>
ID:<input type="text" name="id"/><br/>
NAME:<input type="text" name="name"/><br/>
ADDRESS:<input type="text" name="address"/><br/>
<input type="submit" value="Submit" onclick="buttonreport(this.id,this.name,this.address)"/>
</body>
现在正在工作,但输出显示为id:name:地址未显示输入值
答案 0 :(得分:2)
您在脚本中拼错了警告
答案 1 :(得分:0)
我不是JS专家,但也许您需要提交表单周围的<form>
标签。您也可以使用getelementbyid
。
答案 2 :(得分:0)
您的alret
应为alert
。现在它有效:)
<title>Javascript</title>
<script>
function buttonreport(id,name,address){
var userid ="Id:"+id;
var username="Name :"+name+"\n";
var useraddress ="Address:"+address+"\n";
alert(userid+username+useraddress);
}
</script>
</head>
<body>
ID:<input type="text" name="id"/><br/>
NAME:<input type="text" name="name"/><br/>
ADDRESS:<input type="text" name="address"/><br/>
<input type="submit" value="Submit" onclick="buttonreport(this.id,this.name,this.address)"/>