创建django权限,错误:ContentType匹配查询不存在

时间:2013-11-15 16:26:43

标签: python django django-contenttypes

我正在尝试添加两个组并授予他们Django项目的权限。但我一直收到错误:

ContentType匹配查询不存在。

我正在跑步: Django 1.5.4 Python 2.7.3 南0.8.2 PostreSQL 9.3

这是我的代码:

import django
from django.contrib.auth.models import Group, Permission
from django.contrib.contenttypes.models import ContentType 

from .models import Flavor

def add_groups():
    # Create User Groups
    special_users = Group(name='Special Users')
    special_users.save()
    really_special_users = Group(name='Super Special Users')
    really_special_users.save()

def add_permissions():
    # Define a View permission for the 1st group, and a View/Modify permission for the 2nd group
    somemodel_ct = ContentType.objects.get(app_label='flavors', model='flavors_flavor')
    can_view = Permission(name='Can View', codename='can_view_something', content_type=somemodel_ct)
    can_view.save()
    can_modify = Permission(name='Can Modify', codename='can_modify_something', content_type=somemodel_ct)
    can_modify.save()

def give_perm_to_groups():
    # Associate these two permissions now with a Group
    special_users.permissions.add(can_view)
    really_special_users.permissions = [can_view, can_modify]

我可以运行add_groups()。现在正在使用add_permissions()。我相信这与Postgres中的灯具有关,但不确定如何添加它们或者这是否是确切的问题?

由于

以下是整个错误追溯:

>>> add_permissions()
Traceback (most recent call last):
  File "<console>", line 1, in <module>
  File "/Users/Yuki_Aaron/Documents/djcode/demoproject/flavors/groups.py", line 16, in add_permissions
    somemodel_ct = ContentType.objects.get(app_label='flavors', model='flavors_flavor')
  File "/Users/Yuki_Aaron/Documents/virtualenvs/django1.5/lib/python2.7/site-packages/django/db/models/manager.py", line 143, in get
    return self.get_query_set().get(*args, **kwargs)
  File "/Users/Yuki_Aaron/Documents/virtualenvs/django1.5/lib/python2.7/site-packages/django/db/models/query.py", line 404, in get
    self.model._meta.object_name)
DoesNotExist: ContentType matching query does not exist.

2 个答案:

答案 0 :(得分:2)

更改此行:

somemodel_ct = ContentType.objects.get(app_label='flavors', model='flavors_flavor')

由:

somemodel_ct = ContentType.objects.get(app_label='flavors', model='flavor')

指定模型时似乎有问题

答案 1 :(得分:1)

我要做的第一件事就是将somemodel_ct更改为:

somemodel_ct = ContentType.objects.get(app_label='flavors', model='flavor')

第二件事是错误是由于我需要为我的模型添加权限,以便django.contrib.auth.models .... PermissionGroup能够在模型中查找已定义的权限,然后关联回ContentType。以下是我添加到models.py以使其正常运行的代码:

class Flavor(models.Model):
...
    class Meta:
            permissions = (
                ('can_view', 'Can View'),
                ('can_modify', 'Can Modify'),
            )

这样,我的Flavor模型可以在Permission表中查找权限。这就是为什么它说ContentType: no matching query,因为我没有将class Meta: permissions包含在我的实际Flavor模型中。

感谢您的帮助!