我想知道,如果符合某些标准,是否可以将给定的日期范围拆分为2个独立的日期范围?
我正在建立假日预订系统,如果假期超过2年,则需要分割日期。例如:
start date: 22-12-2013
end date: 04-01-2014
上面的日期我想将它们分成2个日期范围,所以我最终会得到这样的结果:
start date: 22-12-2013
end date: 31-12-2013
然后:
start date: 01-01-2014
end date: 04-01-2014
这可能吗?如果是这样,有人能指出我需要在谷歌搜索的正确方向吗?
答案 0 :(得分:2)
这是一个非常基本的方法,但我认为调查这样的事情可能很有趣:
$date1 = '22-12-2013';
$date2 = "04-01-2014";
function split_date($d1, $d2)
{
$start_year = substr($d1, -4);
$end_year = substr($d2, -4);
if($end_year > $start_year)
{
$d1 .= ' ['.date('d-m-Y',strtotime("last day of December".$start_year)).'] <br />';
$d2 = '['.date('d-m-Y',strtotime("first day of January".$start_year)).'] ' . $d2;
}
return $d1 . $d2;
}
echo split_date($date1, $date2);
答案 1 :(得分:2)
如果您想分割更多月份,可以使用此功能:
function getMonthRanges($start, $end) {
$timeStart = strtotime($start);
$timeEnd = strtotime($end);
$out = [];
$milestones[] = $timeStart;
$timeEndMonth = strtotime('first day of next month midnight', $timeStart);
while ($timeEndMonth < $timeEnd) {
$milestones[] = $timeEndMonth;
$timeEndMonth = strtotime('+1 month', $timeEndMonth);
}
$milestones[] = $timeEnd;
$count = count($milestones);
for ($i = 1; $i < $count; $i++) {
$out[] = [
'start' => $milestones[$i - 1], // Here you can apply your formatting (like "date('Y-m-d H:i:s', $milestones[$i-1])") if you don't won't want just timestamp
'end' => $milestones[$i] - 1
];
}
return $out;
}
使用:
$result = getMonthRanges('15-11-2014', '19-11-2014');
结果:
Array
(
[0] => Array
(
[start] => 1418594400
[end] => 1420063199
)
[1] => Array
(
[start] => 1420063200
[end] => 1422741599
)
[2] => Array
(
[start] => 1422741600
[end] => 1425160799
)
[3] => Array
(
[start] => 1425160800
[end] => 1426715999
)
)
人类可读的结果:
array_walk_recursive($result, 'applyFormat');
function applyFormat(&$item)
{
$item = date('Y-m-d H:i:s', $item);
}
Array
(
[0] => Array
(
[start] => 2014-12-15 00:00:00
[end] => 2014-12-31 23:59:59
)
[1] => Array
(
[start] => 2015-01-01 00:00:00
[end] => 2015-01-31 23:59:59
)
[2] => Array
(
[start] => 2015-02-01 00:00:00
[end] => 2015-02-28 23:59:59
)
[3] => Array
(
[start] => 2015-03-01 00:00:00
[end] => 2015-03-18 23:59:59
)
)
答案 2 :(得分:0)
感谢ilpaijin,这就是我想出的:
$date1 = '22-12-2013';
$date2 = "04-01-2014";
function split_date($d1, $d2)
{
$start_year = substr($d1, -4);
$end_year = substr($d2, -4);
if($end_year > $start_year)
{
$d1 .= ' ['.date('d-m-Y',strtotime("31-12-".$start_year)).'] <br />';
$d2 = '['.date('d-m-Y',strtotime("01-01-".$start_year."+1 years")).'] ' . $d2;
}
return $d1 . $d2;
}
echo split_date($date1, $date2);
答案 3 :(得分:0)
如果有人希望将日期范围拆分任意年数,则执行以下内容。
$date1 = '22-12-2013';
$date2 = '04-01-2017';
$dA = array();
function split_date($d1, $d2, &$dA)
{
$start_year = substr($d1, -4);
$end_year = substr($d2, -4);
if($end_year > $start_year)
{
$dA[] = $d1;
$dA[] = date('d-m-Y',strtotime("31-12-".$start_year));
if($end_year - $start_year == 1)
{
$dA[] = date('d-m-Y',strtotime("01-01-".$start_year."+1 years"));
$dA[] = $d2;
}else
{
split_date(date('d-m-Y',strtotime("01-01-".$start_year."+1 years")), $d2, $dA);
}
}else if($end_year == $start_year)
{
$dA[] = $d1;
$dA[] = $d2;
}
}
split_date($date1, $date2, $dA);
print_r($dA);
//Answer
Array
(
[0] => 22-12-2013
[1] => 31-12-2013
[2] => 01-01-2014
[3] => 31-12-2014
[4] => 01-01-2015
[5] => 31-12-2015
[6] => 01-01-2016
[7] => 31-12-2016
[8] => 01-01-2017
[9] => 04-01-2017
)
答案 4 :(得分:0)
很简单的方法。您可以为所有类型的日期格式拆分日期范围支持。
function split_date($start_date,$end_date){
while($start_date < $end_date){
$end = date("Y-m-d", strtotime("Last day of December", strtotime($start_date)));
if($end_date<$end){
$end = $end_date;
}
$dates[] =array('start'=>$start_date,'end'=>$end);
$start_date =date("Y-m-d", strtotime("+1 day", strtotime($end)));
}
return $dates;
}
$dates = split_date('2011-01-02','2013-01-04');
print_r($dates);
<强> OUPTPUT 强>
Array
(
[0] => Array
(
[start] => 2011-01-02 //start date
[end] => 2011-12-31
)
[1] => Array
(
[start] => 2012-01-01
[end] => 2012-12-31
)
[2] => Array
(
[start] => 2013-01-01
[end] => 2013-01-04 //end date
)
)