Question

我想跳进一个用户提供数字输入的课程。我试过这个：

EditText eTinput;
 int n;
n=eTinput.getText().toString;


@Override
public void onClick(View v) {
    // TODO Auto-generated method stub

    try {
        Class ourClass    =Class.forName("com.dvdroid.kannadavachanagalu.Shareb",+n);
        Intent ourintent = new Intent(BasavaSelect.this, ourClass);
        startActivity(ourintent);
    } catch (ClassNotFoundException e) {
        e.printStackTrace();
    }
}
});

但我收到一些错误，因为'将输入n更改为可编辑'和'删除参数以匹配forname'

有人可以帮忙怎么做吗？

Answer 1

    EditText eTinput;
    eTinput = (EditText)findViewById(R.id.yourEdittextIdFromXml);

@Override
public void onClick(View v) {
    // TODO Auto-generated method stub

    try {

        if(n==urvaluetocheck)
{

        Intent ourintent = new Intent(BasavaSelect.this, ourClass);
        startActivity(ourintent);

}

else if(n==urvaluetocheck)
{

        Intent ourintent = new Intent(BasavaSelect.this, classuwant);
        startActivity(ourintent);
}
..........

else
{

        Intent ourintent = new Intent(BasavaSelect.this, defaultclass);
        startActivity(ourintent);
}

    } catch (ClassNotFoundException e) {
        e.printStackTrace();
    }
}
});

Answer 2

试试如下：

EditText eTinput;
 int n;
n=eTinput.getText().toString;


@Override
public void onClick(View v) {
    // TODO Auto-generated method stub

    try {
        Class ourClass=Class.forName("com.dvdroid.kannadavachanagalu.Shareb");//Change this line
        Intent ourintent = new Intent(BasavaSelect.this, ourClass);
         ourintent.putExtra("Value", n); 
        startActivity(ourintent);
    } catch (ClassNotFoundException e) {
        e.printStackTrace();
    }
}
});

Answer 3

使用它：

eTinput = (EditText)findViewById(R.id.yourEdittextIdFromXml);

我想在用户输入的情况下跳转到不同的类

3 个答案: