Question

我感到无聊......并决定进行编码，但尚未完成，但我想知道它为什么不能编译。

/*Coding that will countdown the amount of bottles on the wall
*/
#include<stdio.h>
int main()
{
int bottles = 99;
while (bottles >= 0) {  
put ("%i\n bottles of beer on the wall, %i\n bottles of beer, take one down pass it around", bottles, bottles) ; {
    bottles--; 
    put ("%i\n bottles of beer on the wall", bottles) ;
}
continue; }

Answer 1

我不同意答案说你有一个太少的支撑：你也有一个（在put()的最后......改为

/*Coding that will countdown the amount of bottles on the wall
*/
#include<stdio.h>
int main()
{
  int bottles = 99;
  while (bottles > 0) // got rid of '='... Since decrementing inside loop
  {  
    printf ("%i bottles of beer on the wall, %i bottles of beer\n", bottles, bottles);
    printf("Take one down pass it around\n"); // <<<<removed a '}' here...>>>>
    bottles--; 
    printf("%i bottles of beer on the wall\n\n", bottles) ;
  }
  continue; // what is this doing here??? You are not in a while loop...
}

注意 - 我将一个put拆分为两个printf语句，并更改'\n'所在的位置。

Answer 2

通常，错过括号时会出现此错误。你错过了一个结束的焦点}。

#include<stdio.h>
int main()
{
int bottles = 99;
while (bottles >= 0) {  
put ("%i\n bottles of beer on the wall, %i\n bottles of beer, take one down pass it around", bottles, bottles) ; {
    bottles--; 
    put ("%i\n bottles of beer on the wall", bottles) ;
}
continue; 
}
}

投入结束时的预期声明或声明？

2 个答案: