Question

howManyNames = (float(input("Enter how many student names do you want to enter? ")))
studentNames = []
ages = []
averageAge = 0
counter = 0

while (counter < int(howManyNames)):
    studentNames.append(input("Enter student names. "))
    ages.append(float(input("Enter that persons age. ")))
    counter += 1
    averageAge = sum(ages) / float(howManyNames)
print ("Your average age is ", averageAge, "!")

for age in ages:
   if age < int(averageAge):
      print ("Your age is below the average age.", age)
   else:
      print ("Your age is above the average age.", age)

我在尝试使用排序功能时遇到问题我尝试过打印排序（年龄）打印ages.sort（）但等等，但似乎没有任何工作。

Answer 1

您应该使用print(sorted(iterable))代替print(sort(iterable))来对可迭代进行排序。

Answer 2

sort实际上对列表进行了排序。这意味着，如果您print ages.sort() None，您将获得ages.sort(); print ages;。相反，你可以做{{1}}

在python中使用sort函数，遇到问题

2 个答案: